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Calculate the number of mmoles of the excess reactant remaining in solution when mixing 125.6 mL of 0.401 M Na₂CO3(aq) and 76.5 mL of 0.281 M AgNO3(aq) (molar mass of Ag₂CO3 = 275.8 g/mole) 2Ag+ (aq) + CO²(aq) → Ag₂CO3(s) Note: Na₂CO3(s) AgNO3(s) Answer: 2Na+ + CO3²- (aq) Ag+ (aq) + NO3(aq) Answer in the unit of "mmol"

Calculate the number of mmoles of the excess reactant remaining in solution when mixing 125.6 mL of 0.401 M Na₂CO3(aq) and 76.5 mL of 0.281 M AgNO3(aq) (molar mass of Ag₂CO3 = 275.8 g/mole) 2Ag+ (aq) + CO²(aq) → Ag₂CO3(s) Note: Na₂CO3(s) AgNO3(s) Answer: 2Na+ + CO3²- (aq) Ag+ (aq) + NO3(aq) Answer in the unit of "mmol"

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter15: Solutions
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Problem 125AP: When 10. L of water is added to 3.0 L of 6.0 M H2SO4, what is the molarity of the resulting...
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Calculate the number of mmoles of the excess reactant remaining in solution when mixing 125.6 mL of 0.401 M Na₂CO3(aq) and 76.5 mL of 0.281 M AgNO3(aq) (molar mass of Ag₂CO3 = 275.8 g/mole) 2Ag (aq) + CO²(aq) → Ag₂CO3(s) Note: Na₂CO3(s) → 2Na+ + CO²(aq) AgNO3(s) → Ag+ (aq) + NO3(aq) Answer in the unit of "mmol" Answer:
Transcribed Image Text:Calculate the number of mmoles of the excess reactant remaining in solution when mixing 125.6 mL of 0.401 M Na₂CO3(aq) and 76.5 mL of 0.281 M AgNO3(aq) (molar mass of Ag₂CO3 = 275.8 g/mole) 2Ag (aq) + CO²(aq) → Ag₂CO3(s) Note: Na₂CO3(s) → 2Na+ + CO²(aq) AgNO3(s) → Ag+ (aq) + NO3(aq) Answer in the unit of "mmol" Answer:
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