A student dissolves 14.52 grams of aspirin, C9H8O4 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the q Solvent Formula Kb (°C/m) Kf(°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH;CH2OCH2CH3 2.02 The molality of the solution is m. The boiling point of the solution is °C.
A student dissolves 14.52 grams of aspirin, C9H8O4 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the q Solvent Formula Kb (°C/m) Kf(°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH;CH2OCH2CH3 2.02 The molality of the solution is m. The boiling point of the solution is °C.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Boiling Point Elevation/Freezing Point Depression
T = m K
Where:
Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
T = m K
Where:
T | = T(solution) - T(pure solvent) * |
m | = (# moles solute / Kg solvent) |
Kb | = boiling point elevation constant. |
Kf | = freezing point depression constant. |
Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
Solvent | Formula | Kb (°C / m) | Kf (°C / m) |
---|---|---|---|
Water | H2O | 0.512 | -1.86 |
Ethanol | CH3CH2OH | 1.22 | -1.99 |
Chloroform | CHCl3 | 3.67 | |
Benzene | C6H6 | 2.53 | -5.12 |
Diethyl ether | CH3CH2OCH2CH3 | 2.02 |
note that ΔT as defined above will be a negative number for freezing point depression. Therefore, Kf must also be given as a negative number.
![The boiling point of diethyl ether, CH3CH2OCH2CH3, is 34.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin.
A student dissolves 14.52 grams of aspirin, C9H304 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the questions below.
Solvent
Formula
Kb (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
C6H6
2.53
5.12
Diethyl ether CH;CH2OCH2CH3
2.02
The molality of the solution is
m.
The boiling point of the solution is
°C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F966b9752-0e6e-47d7-af8f-ce4bbf704a72%2Fba8da9fa-87f0-4e91-8abf-55a2a0154971%2Fkww3twi_processed.png&w=3840&q=75)
Transcribed Image Text:The boiling point of diethyl ether, CH3CH2OCH2CH3, is 34.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin.
A student dissolves 14.52 grams of aspirin, C9H304 (180.1 g/mol), in 156.5 grams of diethyl ether. Use the table of boiling and freezing point constants to answer the questions below.
Solvent
Formula
Kb (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
C6H6
2.53
5.12
Diethyl ether CH;CH2OCH2CH3
2.02
The molality of the solution is
m.
The boiling point of the solution is
°C.
![The boiling point of diethyl ether CH3CH2OCH2CH3 is 34.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is estrogen (estradiol).
How many grams of estrogen, C18H2402 (272.4 g/mol), must be dissolved in 250.0 grams of diethyl ether to raise the boiling point by 0.450 °C ? Refer to the table for the necessary boiling or freezing point constant.
Solvent
Formula
Kb (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
C6H6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
g estrogen.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F966b9752-0e6e-47d7-af8f-ce4bbf704a72%2Fba8da9fa-87f0-4e91-8abf-55a2a0154971%2F5dzbys_processed.png&w=3840&q=75)
Transcribed Image Text:The boiling point of diethyl ether CH3CH2OCH2CH3 is 34.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is estrogen (estradiol).
How many grams of estrogen, C18H2402 (272.4 g/mol), must be dissolved in 250.0 grams of diethyl ether to raise the boiling point by 0.450 °C ? Refer to the table for the necessary boiling or freezing point constant.
Solvent
Formula
Kb (°C/m) Kf (°C/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
C6H6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
g estrogen.
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