A student prepared a sugar solution containing 7.5345 g of sugar (C12H22011, 342.29 g/mol) in 25.00 mL of water and collected the following freezing point data. What is the K, of water based on the student's data? Temperature (C Temperature (°C) 15 10 20 15 10 5 0 5 Freezing Point of Pure Water 0 10 20 30 40 50 60 70 80 90 100 110 120 130 time (seconds) 0.88 °C/m 10. °C/m 1.9 °C/m 0.10 °C/m Freezing Point of Sugar Solution -10 15 0 10 20 30 40 50 60 70 80 90 100110120130140150160170180 time (seconds)

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A student prepared a sugar solution containing 7.5345 g of sugar (C12H22011, 342.29
g/mol) in 25.00 mL of water and collected the following freezing point data. What is the
K, of water based on the student's data?
E 15
Temperature (C
Temperature ("C
10
15
10
0
Freezing Point of Pure Water
0 10 20 30 40 50 60 70 80 90 100 110 120 130
time (seconds)
0.88 °C/m
10. °C/m
1.9 °C/m
0.10 °C/m
Freezing Point of Sugar Solution
15
0 10 20 30 40 50 60 70 80 90 100110120130140150160170180
time (seconds)
Transcribed Image Text:A student prepared a sugar solution containing 7.5345 g of sugar (C12H22011, 342.29 g/mol) in 25.00 mL of water and collected the following freezing point data. What is the K, of water based on the student's data? E 15 Temperature (C Temperature ("C 10 15 10 0 Freezing Point of Pure Water 0 10 20 30 40 50 60 70 80 90 100 110 120 130 time (seconds) 0.88 °C/m 10. °C/m 1.9 °C/m 0.10 °C/m Freezing Point of Sugar Solution 15 0 10 20 30 40 50 60 70 80 90 100110120130140150160170180 time (seconds)
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