A solution made by dissolving napthalene, C10H8 (commonly used in household mothballs), in benzene, C6H6 had a boiling point of 80.66°C. What is the freezing point depression of this solution? Given the following information for the solvent: the boiling point and freezing points are 80.10°C and 5.500°C, respectively. Kb = 2.530 °C/m and Kf = 5.120°C/m .
A solution made by dissolving napthalene, C10H8 (commonly used in household mothballs), in benzene, C6H6 had a boiling point of 80.66°C. What is the freezing point depression of this solution? Given the following information for the solvent: the boiling point and freezing points are 80.10°C and 5.500°C, respectively. Kb = 2.530 °C/m and Kf = 5.120°C/m .
Elevation in boiling point and depression in freezing point are colligative properties as they are dependent on mass of the solute. By adding some solute to the solvent there will be an increase in boiling point and decrease in freezing point of the solvent known as elevation in boiling point and depression in freezing points respectively.
Given that,
Solvent is benzene.
Solute is naphthalene (C10H8).
Boiling point of benzene after addition of naphthalene (C10H8) =
Boiling point of benzene =
Freezing point of benzene =
Ebullioscopy constant (Kb) =
Cryoscopy constant (Kf) =
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