A student conducts a study on campus. The student wants to identify the number of credit hours taken by students in their first three years. The studenthypothesized that first year individuals would take fewer credit hours. The results of the analysis are below. Given the data below calculate the F-ratio, do youreject the null hypothesis? State the null and alternative hypothesis, the sums of squares within, sum of squares between, sum of squares total, degrees of freedomwithin, degrees of freedom between, mean square within, and the mean square between.2nd year(H₂)3rd year(H3)1st years(H₁)N11Mean 12.58St.dev 2.111114.502.021116.172.12Given the results in the prior question, which groups are significantly different?Given the results of the number of credit hours taken by year at college, calculate the eta squared and interpret the results.

A student conducted a study on campus.The goal offer the study was to identify the number of credit hours taken by students in their first three years.The student hypothesis day that first-year individuals would take a specific (fewer) number of credit hours.The given data three groups representing each year, NMeanSt. devThe level of significance, 1. The Null and Alternative hypotheses can be formulated as,Null hypothesis : There is no significant difference in the means.Symbolically it can be written as,Alternative hypothesis : At least one group mean is significantly different.2. Calculation of the ratio.Calculation of the overall mean :Calculation of the sum of squares within (SSW):Calculation of the sum of squares between (SSB):Calculation of the total sum of squares (SST):Calculation of the degrees of freedom within and between:The degrees of freedom are,Calculation of the mean square within and between:Mean square within the group:The mean square between groups:4.3423Calculation of F-ratio:3. Calculation of the critical value:The excel for mula to calculate the crtical value-'=F.INV.RT(probability,deg_freedom1,deg_freedom2)''=F.INV.RT(0.05,2,30)'The screenshot of the Excel sheet-4. Decision Criterion:The decision is to reject the null hypothesis if end text F subscript text critical end text end subscript" role="math" data-mathml="«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»F«/mi»«mo»§#160;«/mo»«mtext»ratio§#62;«/mtext»«msub»«mi»F«/mi»«mtext»critical«/mtext»«/msub»«/math»" width="104" height="25" style="max-width: none; vertical-align: -9px;" data-mce-style="max-width: none; vertical-align: -9px;"> in favor of the alternative hypothesis.Decision:Since we fail to reject the null hypothesis.Decision:At a level of significance, we conclude that there is no significant difference in the means of credit hours for three years.Calculation for the :The interpretation of : is a measure of effect size in ANOVA, representing the proportion of total variability in the dependent variable that can be attributed to the independent variable (group differences).A value of suggests that approximately of the total variance in the number of credit hours can be explained by the differences between the three groups.In practical terms, this indicates a substantial effect of the grouping variable (years) on the number of credit hours taken by students.The guidelines for the interpretation of -Small effectaround Medium effectaround Large effectaround or highera) At a level of significance, we conclude that there is no significant difference in the means of credit hours for three years.b) The value of is . A value of suggests that approximately of the total variance in the number of credit hours can be explained by the differences between the three groups. In practical terms, this indicates a substantial effect of the grouping variable (years) on the number of credit hours taken by students.