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A stream flowing at a rate of 30kgmol/h containing 30% (mole) N₂ and 70% (mole) H₂. This is to be heated from 300 K to 470 K. Calculate the amount of heat transferred using the C; data given below. Cp №₂ = 29.57 - 5.43 × 10¯³T + 13.17 × 10¯67², kJ/kgmol -K CHH₂ = 28.65 +1.02 x 10-³T-0.15 x 10-67², kJ/kgmol - K

A stream flowing at a rate of 30kgmol/h containing 30% (mole) N₂ and 70% (mole) H₂. This is to be heated from 300 K to 470 K. Calculate the amount of heat transferred using the C; data given below. Cp №₂ = 29.57 - 5.43 × 10¯³T + 13.17 × 10¯67², kJ/kgmol -K CHH₂ = 28.65 +1.02 x 10-³T-0.15 x 10-67², kJ/kgmol - K

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A stream flowing at a rate of 30kgmol/h containing 30% (mole) N₂ and 70% (mole) H₂. This is to be heated from 300 K to 470 K. Calculate the amount of heat transferred using the C data given below. CP N₂ = 29.57 - 5.43 × 10-³T + 13.17 x 10-672, kJ/kgmol -K CHH₂ = 28.65 +1.02 x 10-³T-0.15 x 10-672, kJ/kgmol - K
Transcribed Image Text:A stream flowing at a rate of 30kgmol/h containing 30% (mole) N₂ and 70% (mole) H₂. This is to be heated from 300 K to 470 K. Calculate the amount of heat transferred using the C data given below. CP N₂ = 29.57 - 5.43 × 10-³T + 13.17 x 10-672, kJ/kgmol -K CHH₂ = 28.65 +1.02 x 10-³T-0.15 x 10-672, kJ/kgmol - K
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