A stockroom worker pushes a box with mass 10.8 kg on a horizontal surface with a constant speed of 3.50 m/s. The coefficients of kinetic and static friction between the box and the surface are 0.220 and 0.530, respectively. For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Delivering the goods. Part A What horizontal force must the worker apply to maintain the motion of the box? Express your answer in newtons. Assume that + direction coincides with the direction of velocity. ▸ View Available Hint(s) F₂ = 23.3 N Submit ✓ Correct Part B Previous Answers If the worker stops pushing, what will be the acceleration of the box? Express your answer in meters per second squared. Assume that + direction coincides with the direction of velocity. ▾ View Available Hint(s) ▼ Hint 1. How to approach the problem In Part A, you would have found an expression for the motion of the box in the horizontal direction using Newton's second law. In that expression, let the force applied by the worker equal zero and assume the box is accelerating. You should then be able to obtain an expression for the acceleration of the box. Be sure to consider the direction of the forces. IVE ΑΣΦ a₂ = 23.3 ? m/s²
A stockroom worker pushes a box with mass 10.8 kg on a horizontal surface with a constant speed of 3.50 m/s. The coefficients of kinetic and static friction between the box and the surface are 0.220 and 0.530, respectively. For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Delivering the goods. Part A What horizontal force must the worker apply to maintain the motion of the box? Express your answer in newtons. Assume that + direction coincides with the direction of velocity. ▸ View Available Hint(s) F₂ = 23.3 N Submit ✓ Correct Part B Previous Answers If the worker stops pushing, what will be the acceleration of the box? Express your answer in meters per second squared. Assume that + direction coincides with the direction of velocity. ▾ View Available Hint(s) ▼ Hint 1. How to approach the problem In Part A, you would have found an expression for the motion of the box in the horizontal direction using Newton's second law. In that expression, let the force applied by the worker equal zero and assume the box is accelerating. You should then be able to obtain an expression for the acceleration of the box. Be sure to consider the direction of the forces. IVE ΑΣΦ a₂ = 23.3 ? m/s²
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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