Part A If a car is moving to the left with constant velocity, one can conclude that ANSWER: there must be no forces exerted on the car. the net force exerted on the car is directed to the left. the net force exerted on the car is zero. there is exactly one force exerted on the car. Part B An object cannot remain at rest unless ANSWER: there are no forces at all exerted on it. the net force exerted on it is zero. the net force exerted on it is constant. there is only one force exerted on it.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Part A
If a car is moving to the left with constant velocity, one can conclude that
ANSWER:
there must be no forces exerted on the car.
the net force exerted on the car is directed to the left.
the net force exerted on the car is zero.
there is exactly one force exerted on the car.
Part B
An object cannot remain at rest unless
ANSWER:
there are no forces at all exerted on it.
the net force exerted on it is zero.
the net force exerted on it is constant.
there is only one force exerted on it.
Transcribed Image Text:Part A If a car is moving to the left with constant velocity, one can conclude that ANSWER: there must be no forces exerted on the car. the net force exerted on the car is directed to the left. the net force exerted on the car is zero. there is exactly one force exerted on the car. Part B An object cannot remain at rest unless ANSWER: there are no forces at all exerted on it. the net force exerted on it is zero. the net force exerted on it is constant. there is only one force exerted on it.
A crate with mass 33.0 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 12.0 N.
Part A
What is the magnitude of acceleration?
Express your answer in meters per second squared.
ANSWER:
a =
m/s?
Part B
How far does the crate travel in 12.0 s?
Express your answer in meters.
ANSWER:
m
Part C
What is its speed at the end of 12.0 s?
Express your answer in meters per second.
ANSWER:
V =
m/s
A Space Walk
Transcribed Image Text:A crate with mass 33.0 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 12.0 N. Part A What is the magnitude of acceleration? Express your answer in meters per second squared. ANSWER: a = m/s? Part B How far does the crate travel in 12.0 s? Express your answer in meters. ANSWER: m Part C What is its speed at the end of 12.0 s? Express your answer in meters per second. ANSWER: V = m/s A Space Walk
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