A steel bar, 300 mm long and 24 mm diameter, is turned down to 18 mm diameter for one third of its length. It is heated 30°C above room temperature, clamped at both end and then allowed to cool to room temperature. If the distance between the clamps is unchanged, the maximum stress in the bar (a = 12.5x10-° per °C & E=200 GN/m2 is) %3D (a) 25 MN/m² (b) 50 MN/m2 (s) (c) 75 MN/m² (d) 100 MN/m2 47

A steel bar, 300 mm long and 24 mm diameter, is turned down to 18 mm diameter for one third of its length. It is heated 30°C above room temperature, clamped at both end and then allowed to cool to room temperature. If the distance between the clamps is unchanged, the maximum stress in the bar (a = 12.5x10-° per °C & E=200 GN/m2 is) %3D (a) 25 MN/m² (b) 50 MN/m2 (s) (c) 75 MN/m² (d) 100 MN/m2 47

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the alu- minum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. - 14 in. - Bronze A = 2.4 in² E = 15 x 106 psi a = 12 x 10-6/°F Fig. P2.58 and P2.59 18 in.. Aluminum A = 2.8 in² E = 10.6 x 106 psi a = 12.9 x 10-6/°F 300 mm 0.5 mm 250
At an axial load of 25 kN, a 45-mm-wide by 15-mm-thick polyimide polymer bar elongates 3.1 mm while the bar width contracts 0.18 mm. The bar is 240 mm long. At the 25-kN load, the stress in the polymer bar is less than its proportional limit. Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thickness. Answers: (a) E= (b) v = (c) Athickness= i GPa mm
A circular aluminum alloy [E = 70 GPa; α = 22.5 × 10–6/°C; ν = 0.33] pipe has an outside diameter of 185 mm, a wall thickness of 5 mm, and a length of 5.0 m. The pipe supports a compressive load of 675 kN. After the temperature of the pipe drops 39°C, determine:(a) the axial deformation of the pipe.(b) the change in diameter of the pipe.
At room temperature (20°C) a 0.7-mm gap exists between the ends of the rods shown. At a later time when the temperature has reached 150°C, determine: (a.)The normal stress in the aluminum rod, (b.) The change in length of the aluminum rod. 0.7 mm 300 mm A Aluminum A =2,000 mm² E= 75 GPa α = 23 x 106/°C 250 mm B Stainless steel A = 800 mm² E = 190 GPa a = 17.3 x 10-6/°C
At an axial load of 20 kN, a 45-mm-wide by 10-mm-thick polyimide polymer bar elongates 3.3 mm while the bar width contracts 0.21 mm. The bar is 240 mm long. At the 20-kN load, the stress in the polymer bar is less than its proportional limit. Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thickness. Answers: (a) E= (b) v = (c) Athickness= i i i GPa mm
A 20 m long steel rod is at a temperature of 20°C. The rod is heated so that temperature rises by 50°C. If rod is allowed to expand by 14 mm, what will be the stress induced in rod? Take E = 200 GPa and α = 12 x 10-6/°C.
1. At a temperature of 5°C, a 3-mm gap exists between the end of polymer bar (1) and support A as shown. Bar (1) is 50 mm wide and 20 mm thick (E = 800 MPa, a = 140 x 10-6/°C). Bar (2) is 75 mm wide and 25 mm thick (E = 2.7 GPa, a = 67 x 106/°C). The supports at A and C are rigid (i.e., fixed). Determine: a) the temperature at which the normal stress in bar (2) will be equal to -3.0 MPa, and b) the lengths of the two polymer bars at this temperature. (1) 3-mm gap 50 mm 500 mm B 75 mm 400 mm (2)
A solid cube of side 1 m is kept at a room temperature of 32°C. The coefficient of linear therma expansion of the cube material is 1 x 105/°C and the bulk modulus is 200 GPa. If the cube is constrained all around and heated uniformly to 42°C, then the magnitude of volumetric (mean) stress (in MPa) induced due to heating is و او را
Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 103 inches) of the aluminum bar. 0.02 in. 14 in. Bronze A = 2.4 in² E = 15 × 106 psi a = 12 x 10-6/°F 18 in. Aluminum A = 2.8 in² E = 10.6 × 106 psi a = 12.9 x 10-6/°F
A solid steel bar 50 mm in diameter and 1.5 m long is secured between rigid walls. If the stress in the bar is zero at 27°C, what will be the stress (MPa) in the bar when the temperature rises to 42°C? Use E = 200 GPa and a = 12.5 × 10-6 m/m-°C. %3D
Narrow bars of aluminum are bonded to the two sides of a thick steel plate as shown. Initially, at T₁ = 70°F, all stresses are zero. Knowing that the temperature will be slowly raised to T₂ and then reduced to T₁, determine (a) the highest temperature T₂ that does not result in residual stresses, (b) the temperature T₂ that will result in a residual stress in the aluminum equal to 58 ksi. Assume aa = 12.8 x 10-6/°F for the aluminum and a = 6.5 × 10-6/°F for the steel. Further assume that the aluminum is elastoplastic with E = 10.9 × 106 psi and ay = 58 ksi. (Hint: Neglect the small stresses in the plate.) Fig. P2.121
Question 2) Knowing that a 0.02-in. gap exists when the temperature is 75 °F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. -14 in. Bronze A = 2.4 in² E = 15 x 10 psi a = 12 x 10-6/°F -18 in.- Aluminum A = 2.8 in² E = 10.6 x 105 psi a = 12.9 x 10-6/°F