2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the alu- minum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. + -14 in. - Bronze A = 2.4 in² E = 15 x 106 psi a = 12 x 10-6/°F * 18 in. Aluminum A = 2.8 in² E = 10.6 x 106 psi a = 12.9 x 10-6/°F

2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the alu- minum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. + -14 in. - Bronze A = 2.4 in² E = 15 x 106 psi a = 12 x 10-6/°F * 18 in. Aluminum A = 2.8 in² E = 10.6 x 106 psi a = 12.9 x 10-6/°F

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: An aluminum alloy [E = 73 GPa; v = 0.33; a= 23.0 x 10-6/°C] plate is subjected to a tensile load P.…

Q: SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and…

Q: A plate in equilibrium is subjected to uniform stresses along its edges with magnitude Oxx= 30 MPa…

A: Given data- A plate in equilibrium under uniform stress- σxx=30 MPa,σyy=30 MPa,σzz=0 MPa, Young's…

Q: Calculate the normal stress in the brass rod in MPa. Calculate the normal stress in the bronze rod…

Q: 1

A: Given data:- Moment about a horizontal axis on the cross section is 0.80 kN-m

Q: At room temperature (24°C) a 0.5 mm gap exists between the ends of the rods shown in the figure. At…

Q: The figure shows the state of stress on the element at a point on a member. Determine the stress…

A: Normal stress about x axis, Normal stress about y axis, Shear stress, Angle, To find: Stress…

Q: A 10 cm diameter solid alumin Assume that L=0.5 m. The yiel a) Normal stress due to bending caused…

Q: Two cylindrical rods AB and BC are welded together at B and loaded as shown. Knowing that the…

Q: A circular tube of aluminum is subjected totorsion by torques T applied at the ends (see figure).The…

Q: Two uniform spheres are positioned as shown. Determine the gravitational force F which the titanium…

Q: A copper bar is of uniform cross-section and is rigidly attached to the walls as shown. The rod is…

Question

2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F,
determine (a) the temperature at which the normal stress in the alu-
minum bar will be equal to -11 ksi, (b) the corresponding exact
length of the aluminum bar.
0.02 in.
- 14 in. -
Bronze
A = 2.4 in²
E = 15 x 106 psi
a = 12 x 10-6/°F
Fig. P2.58 and P2.59
18 in..
Aluminum
A = 2.8 in²
E = 10.6 x 106 psi
a = 12.9 x 10-6/°F
300 mm
0.5 mm
250

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Stresses in saturated soil without seepage

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

An aluminum alloy [E = 72 GPa; v = 0.33; a= 23.0 x 10-6/°C] plate is subjected to a tensile load P. The plate has a depth of d = 245 mm, a cross-sectional area of A = 5500 mm², and a length of L = 6.0 m. The initial longitudinal normal strain in the plate is zero. After load P is applied and the temperature of the plate has been increased by AT = 69°C, the longitudinal normal strain in the plate is found to be 3340 μc. Determine: (a) the magnitude of load P. (b) the change in plate depth Ad. L P Answer: (a) P = i (b) Δd = i KN mm
Calculate the stress and strain at each force interval. Plot a graph of the stress-strain curve. Estimate the yield point of the steel and note its location on the curve. Estimate the ultimate strength of the steel and note its location on the curve.
#2 will upvote to anyone who will answer
A uniform edge load of w₁ = 540 lb/in. and W2 = 400 lb/in. is applied to the polystyrene specimen. Ep = 597 (10³) psi and vp = 0.25. (Figure 1) Figure T W₂ b - < 1 of 1
Solve it correctly please.
GIVEN: Bar has a cross-sectional area of 4 in? and is placed between two rigid immoveable supports when it is 30.00 inches long at a temperature of -20°F. REQ’D: A) The stress in the bar at 90°F if it were made of steel. Esteel = 10 x 10° psi asteel = 13 x 106/°F B) The final length of the aluminum bar
A steel component is subjected to alternate cyclical loading. The steel follows Basquin's law for high cycle fatigue, o, x N = C, (where the stress amplitude is in MPa). Ignore the geometric detail and assume that Marin's modifying factors are all equal to 1. You are given the minimum stress ain = -213 MPa, the maximum stress omax = 213 MPa. The material data are Tensile strength oUTS = 539 MPa, Basquin's constant c, = 875 MPa, Basquin's exponent a = 0.085. a) Calculate the stress ratio R, the stress amplitude o, in MPa and the mean stress am in MPa. The answers are acceptable with a tolerance of 0.01 for R and of 1 MPa the stresses. R: MPa MPа b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1 106 cycles) N :
Problem 1 An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown. Axial loads are applied at the positions indicated. Aluminum Steel A=800mm2 A=1000mm2 Bronze A=700mm? 4P 2P 500mm 600mm 700mm 1. What is the maximum value of P that will not exceed the axial stress bronze of 105 MPa? 2. What is the maximum value of P that will not exceed the axial stress in aluminum of 90 MPa? 3. If P=10KN, what is the axial force to be carried by the aluminum in KN? 4. If P is 5KN, what is the axial stress of steel?
The composite beam is made of steel (A) bonded to brass (B) and has the cross section shown. It is subjected to a moment of M = 6.3 kN?m .Ebr = 100 GPa, Est = 200 GPa A: Determine the maximum bending stress in the brass. B:Determine the maximum bending stress in the steel. C: Determine the stress in the brass at the seam where the brass and steel are bonded together. D:Determine the stress in the steel at the seam where the brass and steel are bonded together. B M 175 mm 150 mm 200 mm
please just solve the second part
Determine the normal stress and change in length of the aluminum rod if the temperature was raised by 125°C. The 0.5-mm gap exists at 20°C. q = 5 t = 0
Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 103 inches) of the aluminum bar. 0.02 in. 14 in. Bronze A = 2.4 in² E = 15 × 106 psi a = 12 x 10-6/°F 18 in. Aluminum A = 2.8 in² E = 10.6 × 106 psi a = 12.9 x 10-6/°F