Calculate the stress and strain at each force interval. Plot a graph of the stress-strain curve. Estimate the yield point of the steel and note its location on the curve. Estimate the ultimate strength of the steel and note its location on the curve. 10.1. A 0.505-in-diameter mild steel specimen was tested to failure in a tensile testing ma-chine by slowly pulling it apart with a steadily increasing force. Deformation (elonga-tion) of the specimen was measured at force intervals of 1000 lb until the specimenfailed. The initial gauge length of the specimen was 2.00 in. Observed data are providedin Table E10.1.(a) Calculate the stress and strain at each force interval.(b) Plot a graph of the stress-strain curve.(c) Estimate the yield point of the steel. Note its location on the curve.(d) Estimate the ultimate strength of the steel. Note its location on the curve.Table E10.1 TENSILE TEST OF MILD STEEL: OBSERVED DATAForceDeformationForceDeformation(Ib)(in)(lb)(in)10 0000.11701 0000.000411 0000.15552 0000.000712 0000.17053 0000.001113 0000.18754 0000.001414 0000.20585 0000.001715 0000.23806 0000.002116 0000.27107 0000.002416 2000.29828 0000.003215 0000.35709 0000.074814 100Fracture

a}b}Consider the given data Diameter of aluminium =0.505 inCross-section Area=A=π4×0.505A=0.2 in2Gauge length=L=2 inStress=ForceArea=PAStrain=DeformationGauge length=∆LLYield stress=60,000 lb/in2Yield Point=The point at which plastic deformation startsUltimate strength=Maximum stress =72750 lb/in2