(a) State the null hypothesis Ho and the alternative hypothesis H₁. HO H₁:0 (b) Determine the type of test statistic to use. (Choose one)
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- Test the claim that the mean GPA of night students is larger than 2 at the 0.10 significance level. The null and alternative hypothesis would be: Họ :p = 0.5 Họ:µ = 2 Ho:u 0.5 Ho:p 2 H1 :p + 0.5 H1:µ # 2 H1:µ > 2 H1:p 0.5 H1:µ < 2 The test is: left-tailed right-tailed two-tailed Based on a sample of 25 people, the sample mean GPA was 2.02 with a standard deviation of 0.05 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesisUse technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is μ>98.6°F. The sample size is n=9 and the test statistic is t=2.262.Q3 Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Among 2125 passengers cars in a particular region, 229 had only rear license plates. Among 326 commercial trucks, 47 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passengers cars. Use a 0.01 significance level to test that hypothesis. A. Identity the nulls and alternative hypotheses B. Identify the test statistic ( round to two decimal places as needed) C. Identify the p- values (round to two decimal places as needed ? State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. A. Fail to reject Ho. There is not sufficient evidence to support the claim that commercial trucks owners…
- Test the claim that the proportion of men who own cats is larger than 20% at the .01 significance level. The null and alternative hypothesis would be: Ho: P 0.2 Hop 0.2 Hoμ = 0.2 H₁: p0.2 H₁ : μ 0.2 (to 2 decimals) (to 2 decimals) Ho: p = 0.2 0 H₁: p < 0.2Test the claim that the mean GPA of night students is larger than 3.1 at the 0.01 significance level. The null and alternative hypothesis would be: Но: р — 0.775 Но:р> 0.775 Но: и — 3.1 Но:р 3.1 Н:р+ 0.775 Hi:р 3.1 H]:p > 0.775 Hi:р < 3.1 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.14 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesisTest the claim that the mean GPA of night students is larger than 2.4 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: µ = — 2.4 Но:р 2.4 Н: + 2.4 H:p> 0.6 H:д> 2.4 Hi:p #0.6 Hi:p < 0.6 Н:р < 2.4 The test is: left-tailed two-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.41 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
- (c) Is B, significant? Use a = 0.05. State the null and alternative hypotheses. Ho: B2 Ha: B2 > 0 Ho: B2 0 Ha: B2s 0 O Ho: B2 # 0 Ha: B2 O Ho: B2 = 0 Ha: B2 # 0 Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to three decimal places.) p-value State your conclusion. Do not reject Ho: There is sufficient evidence to conclude that B, is significant. Do not reject Ho. There is insufficient evidence to conclude that B, is significant. Reject Ho. There is sufficient evidence to conclude that ß, is significant. Reject Ho. There is insufficient evidence to conclude that ß, is significant.Q1 Probability and StatisticsSolve the problem. When performing a hypothesis test for the ratio of two population variances, the upper critical F value is denoted FR. The lower critical F value, FL, can be found as follows: interchange the degrees of freedom, and then take the reciprocal of the resulting F value found in table A-5. FR can be denoted Fa/2 and FL can be denoted F1-a/2 - Find the critical values FL and FR for a two-tailed hypothesis test based on the following values: n₁ = 4, n₂ = 8, a = 0.05 0.1703, 5.8898 0.1112, 5.0453 0.0684. 5.8898 O 0.1211, 4.3541
- The Pavalue for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a = 0.05. and (c)g=0 10 P=0.0816 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Fail to reject Ho because the P-value, 0.0816, is less than a = 0.01. O B. Fail to reject H, because the P-value, 0.0816, is greater than a= 0.01. OC. Reject H, because the P-value, 0.0816, is less than a=0.01. O D. Reject Ho because the P-value, 0.0816, is greater thana= 0.01. (b) Do you reject or fail to reject H, at the 0.05 level of significance? O A. Reject Ho because the P-value, 0.0816, is less than a =0.05. O B. Fail to reject H, because the P-value, 0.0816, is greater than a= 0.05. OC. Reject H, because the P-value, 0.0816, is greater than oa 0.05. O D. Fail to reject Ho because the P-value, 0.0816, is less than a = 0,05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Reject Ho because the…Test the claim that the proportion of men who own cats is larger than 20% at the .05 significance level. The null and alternative hypothesis would be: 0.2 Но:р — 0.2 Но: и 0.2 Ho:H Ho:H H:р + 0.2 Н]:р 0.2 Hi:р > 0.2 Hi:р#0.2 0.2 Но:р || The test is: left-tailed two-tailed right-tailed Based on a sample of 25 people, 25% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesisPlease find (c), (d), (e) and if possible check to see if my degrees of freedom is correct please:)