(a) State the appropriate null and alternate hypotheses. (b) Compute the P- value. (c) Determine whether to reject H0 (d)State a conclusion
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(a) State the appropriate null and alternate hypotheses.
(b) Compute the P- value.
(c) Determine whether to reject H0
(d)State a conclusion
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- Test the null hypothesis of independence of the two classifications A and B of the accompanying contingency table. Use α = 0.05. Click the icon to view the table. Specify the null and alternative hypotheses. Choose the correct answer below. A. Ho: The row and column classifications are dependent H₂: The row and column classifications are independent B. Ho: The row and column classifications are independent H₂: The row and column classifications are dependent OC. Ho: The classifications A₁ and B₁ are independent H₂: The classifications A₁ and B₁ are dependent Find the test statistic. x² (Round to the nearest hundredth as needed.) Specify the rejection region. Choose the correct answer below. O A. x² >9.48773 O B. x² > 15.5073 O C. x² O D. x² >3.84146 > 16.9190 State the conclusion. Choose the correct answer below. Data table wwwwwww A A₁ A₂ A3 O A. Reject Ho, there is insufficient evidence to indicate the row and column classification are dependent at x = 0.05. Print B₁₁ 41 63 31 B B₂…Determine whether the claim stated below represents the null hypothesis or the alternative hypothesis. If a hypothesis test is performed, how should you interpret a decision that (a) rejects the null hypothesis or (b) fails to reject the null hypothesis? A researcher claims that at least 82% of people had at least one health care visit in the past year. Does the claim represent the null hypothesis or the alternative hypothesis? Since the claim does not contain a statement of equality, it represents the hypothesis. (a) How should you interpret a decision that rejects the null hypothesis? There is evidence to V the claim that at least 82% of people had at least one health care visit in the past year. (b) How should you interpret a decision that fails to reject the null hypothesis? There is evidence to V the claim that at least 82% of people had at least one health care visit in the past year.The mean SAT Score in mathematics is 523. The standard deviation of these scores is 39. A special preparation course claims that the mean SAT score, u, of its graduates is greater than 523. An independent researcher tests this by taking a random sample of 33 students who completed the course; the mean SAT score in mathematics for the sample was 541. Assume that the population is normally distributed. At the 0.01 level of significance, can we conclude that the population mean SAT score for graduates of the course is greater than 523? Assume that the population standard deviation of the scores of course graduates is also 39. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. H, : H : (b) Determine the type of test statistic to use. D=D OSO (Choose one) (c)…
- Claim: A minority of adults would erase all of their personal information online if they could. A software firm survey of 554 randomly selected adults showed that 38% of them would erase all of their personal information online if they could. Complete parts (a) and (b) below. ... a. Express the original claim in symbolic form. Let the parameter represent the adults that would erase their personal information. (Type an integer or a decimal. Do not round.)11The market shares in 2012 of four (4) television companies, A, B, C and D are listed below. A survey was carried out in 2017 on 200 television buyers and the distribution of buyers to A, B, C and D are also listed in the last column. Company Market Share in 2012 Number of buyer in 2017 A 0.4 70 B 0.32 60 C 0.24 54 D 0.04 16 (a) Specify the competing hypotheses to test whether the market shares have changed since 2012. (b) Calculate the value of the test statistics. (c) Use ? = 0.05 to determine if the market shares have changed since 2012.
- Q12 Justified answer asap to get a upvoteLet’s assume the average income for all majors in the School of Engineering is $80,000. However, the chair of the Computer Science department thinks their students earn more than that. Please choose the appropriate null and alternative hypotheses if the chair wanted to test this belief. a. H0: u <=80,000 Ha: u > 80,000 b. H0: u= 80000 Ha: u not= 80000 c. H0: u >80000 Ha: u < 80000 d. H0: u >80000 Ha: < 80000 e. None of the above.Solve all plzzz
- 11. The null and alternative hypotheses For each pair of hypotheses that follows, decide whether H₀ and H₁ are set up correctly as the null and alternative hypotheses for a hypothesis test. If so, select “Valid” from the drop down menu. If not, select “Invalid”. 1 H₀: μ = 76 2 H₀: M = 234 H₁: μ ≠ 76 H₁: M ≠ 234 Invalid 3 H₀: μ = 16 4 H₀: µ = 112 H₁: μ ≠ 16 H₁: µ ≠ 111 You evaluate the by assuming that it is true and testing the reasonableness of this assumption by calculating the probability of getting the results if chance alone is operating.facing up. The student rolls the cube 100 times and lands with 6 facing up 20 times. The P-value for the test of the hypotheses, Hop-0.17 and H p>0.17, is 0.19. What is the correct conclusion given a=0.05? O Because the P-value is less than a=0.05, the student should reject Ho. O Because the P-value is less than a=0.05, the student should reject Ho. O Because the P-value is greater than a=0.05, the student should reject Ho: O Because the P-value is greater than a=0.05, the student should fail to reject Ho. Save and Exit Next Submit Mark this and return 23 $ & 3 4. 5 6. 7 8. y d f h k 60Use the p-value method and fill in the blanks to address the claim: A poll of 1085 adult Americans reveals that 54% of the voters surveyed prefer the Democratic candidate for the presidency. At 0.05 level of significance, test the claim that more than half of all voters prefer the Democrat. Claim: H0: H1: P0: x: n: z= p= recall a= since p a, we the null hypothesis. Final statement: