A spring with a 10-kg mass and a damping constant 18 can be held stretched 0.5 meters beyond its natural length by a force of 2.5 newtons. Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value -4mk? m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form cje +ce where a= B = C₁ = (the larger of the two) (the smaller of the two) €₂==
A spring with a 10-kg mass and a damping constant 18 can be held stretched 0.5 meters beyond its natural length by a force of 2.5 newtons. Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value -4mk? m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form cje +ce where a= B = C₁ = (the larger of the two) (the smaller of the two) €₂==
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Transcribed Image Text:A spring with a 10-kg mass and a damping constant 18 can be held stretched 0.5 meters beyond its natural length by a force of 2.5 newtons.
Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value
²-4mk?
m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the
variablet of the form ce+ce where
a =
B=
C₁ =
(the larger of the two)
(the smaller of the two)
C₂ ==
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