A spring-mass system shown in the diagram below is free to oscillate in the vertical direction. TT unstretched x<0 X - 0 equilibrium position mg - ks - 0 x>0 motion m The position (x) of the spring is positive when the spring is below the equilibrium position. If the block is displaced from its equilibrium position by a distance x, show that its equation of motion is given by: * +x = 0 K Why is it that the equation of motion does not include the force of gravity? In which direction does the velocity of the moving mass have a positive value?
A spring-mass system shown in the diagram below is free to oscillate in the vertical direction. TT unstretched x<0 X - 0 equilibrium position mg - ks - 0 x>0 motion m The position (x) of the spring is positive when the spring is below the equilibrium position. If the block is displaced from its equilibrium position by a distance x, show that its equation of motion is given by: * +x = 0 K Why is it that the equation of motion does not include the force of gravity? In which direction does the velocity of the moving mass have a positive value?
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