A spherical stainless-steel tank having an inner diameter ‘D’, is used to store natural gas at a pressure of ‘p’. The properties of the steel are as follows: yield stress in tension is ‘T’; yield stress in shear is ‘S’ and modulus of elasticity is ‘E’. The desired factor of safety with respect to yielding is ‘F.S’. Determine the minimum permissible thickness t min of the tank. (D (mm)=620)( p (MPa)=25)( T (MPa)=1000)( S (MPa)=440)( E (GPa)=208)( F.S=3.4)
A spherical stainless-steel tank having an inner diameter ‘D’, is used to store natural gas at a pressure of ‘p’. The properties of the steel are as follows: yield stress in tension is ‘T’; yield stress in shear is ‘S’ and modulus of elasticity is ‘E’. The desired factor of safety with respect to yielding is ‘F.S’. Determine the minimum permissible thickness t min of the tank. (D (mm)=620)( p (MPa)=25)( T (MPa)=1000)( S (MPa)=440)( E (GPa)=208)( F.S=3.4)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
A spherical stainless-steel tank having an inner diameter ‘D’, is used to store natural
gas at a pressure of ‘p’. The properties of the steel are as follows: yield stress in tension
is ‘T’; yield stress in shear is ‘S’ and modulus of elasticity is ‘E’. The desired factor of
safety with respect to yielding is ‘F.S’.
Determine the minimum permissible thickness t min of the tank.
(D (mm)=620)( p (MPa)=25)( T (MPa)=1000)( S (MPa)=440)( E (GPa)=208)( F.S=3.4)
Transcribed Image Text:Appendix B
Useful Formulas
Bending
P- M2y – Myz
Iz
1
M
bh3
I
I ==r
4
Ox = 7-
-=
EI
12
A
ly
Principal stresses
My
VQ
3V
Tave =
It
Ттах —
2 A
Or = -
Transformations of plane stress
Ox + Oy + (OxOy) cos(20) + Txysin(26)
2
2
Txy
(0x – Oy
(*,)
sin(20) + Txycos(20)
2
= -
Ox + oy = 0x + Oy
Ox + Oy
Oy
+ T,
(0x
(Ox
Отах,min
Tmax =
2
2
! (UM? + M? + T2
тах
Tall
Spherical Pressure vessels
pr
pr
Ттах
4t
Ospherical
2t
Deflection of beams
d²y_M(x)
dx2
EI
M IN
2.
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