A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced fluid, while the drag2R?g-(Ps - P1), where R is the radius of the sphere, Pg is its density, and p, is the density of the fluid, and n the coefficient of9nforce is assumed to be given by Stokes' law, Fs =6trnv. The terminal speed is given by v =viscosity.Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.7 mm falls with a terminal speed of 8.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively.mPa · s

Given data: R=0.7 mm=0.7×10-3 mv=8.16 cms=8.16×10-2 msρs=7.86 gmL=7860 kgm3ρl=0.88 gmL=880 kgm3Solution: The terminal velocity is given by, v=2R2g9ηρs-ρl Rearranging the equation to find the coefficient of viscosity, η=2R2g9vρs-ρlη=2×0.7×10-32×9.819×8.16×10-27860-880η=91.37×10-3 Pa-sη=91.37 mPa-s

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A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6arnv. The terminal speed is given by v = K 9 (Ps - P), where R is the radius of the sphere, p, is its density, and p, is the density of the fluid, and n the coefficient of 9n viscosity. Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.7 mm falls with a terminal speed of 8.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively. mPa s

A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced fluid, while the drag force is assumed to be given by Stokes' law, Fs = 6arnv. The terminal speed is given by v = K 9 (Ps - P), where R is the radius of the sphere, p, is its density, and p, is the density of the fluid, and n the coefficient of 9n viscosity. Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.7 mm falls with a terminal speed of 8.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively. mPa s

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Properties of Fluids

The term fluid represents a type of substance that can easily change its shape under any external pressure/force and can flow. Fluids can acquire any shape in which it is stored and can resist normal stresses but cannot resist shear stress in rest condition. Whenever external shear stress is applied to fluids, it starts to flow. The fluids may be liquid or gas. Example- water, air, etc.

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A spherical particle falling at a terminal speed in a liquid must have the gravitational force balanced by the drag force and the buoyant force. The buoyant force is equal to the weight of the displaced fluid, while the drag
2R?g
-(Ps - P1), where R is the radius of the sphere, Pg is its density, and p, is the density of the fluid, and n the coefficient of
9n
force is assumed to be given by Stokes' law, Fs =
6trnv. The terminal speed is given by v =
viscosity.
Using the equation above, find the viscosity of motor oil (in mPa · s) in which a steel ball of radius 0.7 mm falls with a terminal speed of 8.16 cm/s. The densities of the ball and the oil are 7.86 and 0.88 g/mL, respectively.
mPa · s

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