A spectrometer uses a specific light source and a grating that has a spe
Q: Calculate the wavelength corresponding to an electron with the energy of 104 eV (kiloelectronvolt).…
A: Given that Energy ( in eV ) = 104 eV . In joule : 104eV = 104×1.6 × 10^-¹⁹J . So we know…
Q: X-rays with wavelengths of 128 pm was used to study a crystal which produced a reflection of 15.8…
A: Given data: Wavelength λ=128 pm Angle θ=15.8o Order n = 1
Q: A laser with 589 nm wavelength and a beam diameter of 2 mm is fed through a beam-expander, then…
A: Given Data: The wavelength of light (λ) = 589 nm = 5.89×10-7m.Beam diameter (d) = 2 mm = 0.002…
Q: The structure factor defines the amount of scattering from the planes hkl in the direction e defined…
A: Let us consider the Geometrical structure factor given by: Fhkl=∑j=1N fjhkl exp 2πihxj+kyj+lzjFhkl…
Q: Diffracted rays Incident rays 1 2 1 2 d Figure 1: Problem 2.
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Q: X rays from a copper X- ray tube (A =204 pm) were diffracted at an angle of 35 degrees by a crystal…
A: Solution: Write the Bragg equation. nλ=2dsin2θ Here, n is the order of diffraction, d is the…
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A: Given: The wavelength of the light is 540 nm. Another wavelength of the light is 600 nm.…
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A: To evaluate the given quantities, we can use the following formulas: i) Wavenumber (k₀) is given by…
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A spectrometer uses a specific light source and a grating that has a specification of 200/mm to split the light (find the distance between gap/lattice). The diffraction pattern seen on the screen is a colored fringe pattern like a rainbow. (a) What light do you think the spectrometer uses? (polychromatic or monochromatic, give reasons!)
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- The (200) plane gives rise to a diffraction peak in simple cubic (sc), body-centred cubic (bcc) and face-centred cubic (fcc) structures. What are the hkl values of the next 2 planes that also give diffraction peaks in all 3 of these structure types?In Young's double slit experiment, the slits are 2mm apart and are illuminated by photons of two wavelengths 4, =12000Å and 1, =10000 Å . At what minimum distance from the common central bright fringe on the screen 2m from the slit will a bright fringe from one interference pattern coincide with a bright fringe from the other? (1) 8mm (2) 6mm| (3) 4mm (4) 3mmPerry O’tic wanted to look at the atomic emission spectrum of Helium. He created a spectroscope with a diffraction grating (4900 lines per cm) and two metersticks. The diffraction grating was located 23 cm from the optical slit. When Perry O’tic looked through the diffraction grating, he observed a spectral line 8.0 cm from the optical slit. What is the wavelength of the observed spectral line?
- Calculate the wavelength corresponding to an electron with the energy of 103 eV (kiloelectronvolt). Give your answer in Angstrom (10-10 m, for example, if the answer is 1.6x10-10 m, then write 1.6 as your answer). This should give you a good idea why one can use a crystal lattice with an average interatomic distance of around 10-10 m to observe electron diffraction.At room temperature, the diffractogram of a cubic material with lattice parameter of 10Å presents a peak at 2θ = 20o. At a higher temperature, the lattice parameter has expanded 20%. Calculate the 2q value of the diffraction peak of the material at the high temperature. λλ is fixed. Do not assume a particular (hkl) set of values, nor a value for λ.A single beam of electrons shines on a single slit of width 8.7nm. A diffraction pattern (of electrons!) is formed on a screen that is 3.9m away from the slit. The distance between the central bright spot and the first minimum is 5.7cm.What is the kinetic energy (keV, i.e. kilo electron-Volts) of the electrons?Make use of the small angle approximation.
- A highly collimated (parallel) beam of electrons is shot through a single slit of width 17.5μm. The electrons are moving with a speed of 7.357.35km/s. When they hit the screen, located at distance 1.57m away, the distribution of hitting positions makes a pattern with a central peak and minima on either side. What is the width of the central peak (equivalently, distance between the minima on either side)? The mass of an electron is 9.11×10^−31 kg.I need the answer as soon as possibleYoung's experimental setup can be used to monitor the width of the lead wires in transistors. The cables are placed in a narrow opening as shown in the figure. The opening is illuminated with highly coherent light. The position of the tenth maximum is measured on a screen located at 0.5m. The expected diameter of the wires is 0.100±0.005 mm. (a) What is the maximum deviation that the position of the tenth maximum can have so that the cable has an acceptable diameter? What would happen if the first maximum was used as the criterion, would the decision be easier or more difficult?