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The structure factor defines the amount of scattering from the planes hkl in the direction e defined by Bragg's law and is given by: N Faki = fi (hkl) exp 2ni (hx; + ky, + lz) j=1 where the unit cell in the crystal contains N atoms of which the jth atom has an atomic scattering factor, f,(hkl) and fractional unit cell co-ordinates X, Vj, Z;. Show clearly, that for a body-centred cubic (bcc) lattice, diffraction peaks will be systematically absent for all planes where (h+k+l) is odd and that diffraction peaks will occur for all planes where (h+k+l) is even. Note: exp (nni) = +1 if n is even exp (nni) = -1 if n is odd

The structure factor defines the amount of scattering from the planes hkl in the direction e defined by Bragg's law and is given by: N Faki = fi (hkl) exp 2ni (hx; + ky, + lz) j=1 where the unit cell in the crystal contains N atoms of which the jth atom has an atomic scattering factor, f,(hkl) and fractional unit cell co-ordinates X, Vj, Z;. Show clearly, that for a body-centred cubic (bcc) lattice, diffraction peaks will be systematically absent for all planes where (h+k+l) is odd and that diffraction peaks will occur for all planes where (h+k+l) is even. Note: exp (nni) = +1 if n is even exp (nni) = -1 if n is odd

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The structure factor defines the amount of scattering from the planes hkl in the direction e defined by Bragg's law and is given by: N Fnkl = 2f, (hkl) exp 2mi (hx + ky, + lz) J=1 where the unit cell in the crystal contains N atoms of which the jh atom has an atomic scattering factor, f(hkl) and fractional unit cell co-ordinates x, y, z;. Show clearly, that for a body-centred cubic (bcc) lattice, diffraction peaks will be systematically absent for all planes where (h+k+l) is odd and that diffraction peaks will occur for all planes where (h+k+1) is even. Note: exp (nrti) = +1 if n is even exp (nri) = -1 if n is odd
Transcribed Image Text:The structure factor defines the amount of scattering from the planes hkl in the direction e defined by Bragg's law and is given by: N Fnkl = 2f, (hkl) exp 2mi (hx + ky, + lz) J=1 where the unit cell in the crystal contains N atoms of which the jh atom has an atomic scattering factor, f(hkl) and fractional unit cell co-ordinates x, y, z;. Show clearly, that for a body-centred cubic (bcc) lattice, diffraction peaks will be systematically absent for all planes where (h+k+l) is odd and that diffraction peaks will occur for all planes where (h+k+1) is even. Note: exp (nrti) = +1 if n is even exp (nri) = -1 if n is odd
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