A solution is prepared that is initially 0.46M in trimethylamine ((CH3)3N), a weak base, and 0.49M in trimethylammonium bromide ((CH3)NHBr). Complete the reaction table below, so that you could use it to calculate the pH of this solution.

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Chapter1: Chemical Foundations
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1. Solve the following problem and fill in all the blanks
A solution is prepared that is initially 0.46M in trimethylamine ((CH³)²N), a
weak base, and 0.49 in trimethylammonium bromide ((CH³)²NHBr
HBr). Complete
the reaction table below, so that you could use it to calculate the pH of this
solution.
Use to stand for the unknown change in [oí¯]. You can leave out the M
X
symbol for molarity.
Transcribed Image Text:A solution is prepared that is initially 0.46M in trimethylamine ((CH³)²N), a weak base, and 0.49 in trimethylammonium bromide ((CH³)²NHBr HBr). Complete the reaction table below, so that you could use it to calculate the pH of this solution. Use to stand for the unknown change in [oí¯]. You can leave out the M X symbol for molarity.
initial
change
final
[(CH,),v] [(CH,),NH]
N
ΝΗ
3
3
0
0
0
[OH-]
0
0
0
Transcribed Image Text:initial change final [(CH,),v] [(CH,),NH] N ΝΗ 3 3 0 0 0 [OH-] 0 0 0
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