A solution containing 0.20 M Pb2+ , 1.5 x 10-6 M Pb4+ , 1.5 × 10-6 M Mn²+, 0.20 M MnO, , and 0.81 M HNO, was prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur. 5 [Pb4+ + 2 e- Pb²+] 2 [MnO, + 8 H+ + 5 e-= Mn²+ + 4H,O] 5 Pb4+ + 2 Mn2+ + 8 H,O= 5 Pb2+ + 2 MnO, + 16 H* E; = 1.690 V E = 1.507 V Determine E, AG", and K for this reaction.
Science behind corrosion-test
Corrosion is defined as an activity that transforms refined metals into more chemically stable forms such as oxide, hydroxide, carbonate, or sulfide. It refers to the slow decomposition of things (typically metals); thanks to chemical and/or electrochemical reactions with their surroundings. Corrosion engineering is the science of preventing and controlling corrosion.
Corrosion
Corrosion is defined as an activity that transforms refined metals into more chemically stable forms such as oxide, hydroxide, carbonate, or sulfide. It refers to the slow decomposition of things (typically metals); thanks to chemical and/or electrochemical reactions with their surroundings. Corrosion engineering is the science of preventing and controlling corrosion.
![A solution containing 0.20 M Pb²⁺, 1.5 × 10⁻⁶ M Pb⁴⁺, 1.5 × 10⁻⁶ M Mn²⁺, 0.20 M MnO₄⁻, and 0.81 M HNO₃ was prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur.
\[
5 \text{ [Pb}^{4+} + 2 e^- \rightleftharpoons \text{Pb}^{2+}\text{]} \quad E^\circ = 1.690 \, \text{V}
\]
\[
2 \text{ [MnO}_4^- + 8 \text{H}^+ + 5 e^- \rightleftharpoons \text{Mn}^{2+} + 4 \text{H}_2\text{O]}\quad E^\circ = 1.507 \, \text{V}
\]
\[
5 \text{Pb}^{4+} + 2 \text{Mn}^{2+} + 8 \text{H}_2\text{O} \rightleftharpoons 5 \text{Pb}^{2+} + 2 \text{MnO}_4^- + 16 \text{H}^+
\]
Determine \(E^\circ_{cell}\), \( \Delta G^\circ \), and \(K \) for this reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3ac3995c-903b-421c-80b6-6f6642a05fa9%2F86fd7a48-f3a7-4ff4-adcd-8d7bcb76e3cc%2Fcp6kq5o_processed.png&w=3840&q=75)
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