ENT 1 volial sit 4. Using the balanced redox equation from question #3, answer the following: A] A student standardized 36.77 mL of a potassium permanganate solution. They used 0.222 grams of sodium oxalate, Na2C2O4. What is the M (molarity) of the KMnO4 solution? 2 MnO4 +SC₂0² +Gh+2M₁²+ +1000₂ +8H₂O Molarity= = moler volume(L) B] How many mL of a standard 0.250 M KMnO4 solution are required to react with 1.0 gram of sodium oxalate, Na2C2O4?
ENT 1 volial sit 4. Using the balanced redox equation from question #3, answer the following: A] A student standardized 36.77 mL of a potassium permanganate solution. They used 0.222 grams of sodium oxalate, Na2C2O4. What is the M (molarity) of the KMnO4 solution? 2 MnO4 +SC₂0² +Gh+2M₁²+ +1000₂ +8H₂O Molarity= = moler volume(L) B] How many mL of a standard 0.250 M KMnO4 solution are required to react with 1.0 gram of sodium oxalate, Na2C2O4?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please provide an answer to question 4B]
![3. Balance the following redox equation using the half-reaction method:
MnO4¹ + C204² ⇒ Mn²+ + CO2 (acidic medium)
O
2+
reduction half reachon: Mnoy →Mn²+
Oxidation half reaction: C₂O4 → CO₂
2+
MnOy² + 8H¹+Se¯ →→Mn²+ + 4/₂0
1₂2
(MnOy² +8H*Se →Mn²+ + 4H₂0) x 2
2C₂04² 200₂ +Se
(C₂04²2 CO₂ + ze) xs
Now combine the two half-reactions
2-
2 MnOy² + 5C₂04²² +1GH+ → 2 Mn²+ +10 CO₂ + 8H₂0
LFOON
HOKO
4. Using the balanced redox equation from question #3, answer the following:
A] A student standardized 36.77 mL of a potassium permanganate solution. They used
0.222 grams of sodium oxalate, Na2C2O4. What is the M (molarity) of the KMnO4
solution? Molarity = moles 2 MnO4 + SC₂0₂² +1GH+ 2M₁²+ +1000₂ +8H₂0
"y
2-
volume(L)
196
10
B] How many mL of a standard 0.250 M KMnO4 solution are required to react with 1.0
gram of sodium oxalate, Na2C2O4?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2827534e-5d68-4ff0-b361-bfdeadbfe949%2F0a278e77-a80b-492f-8129-bf63538681e3%2Fgb76e0n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Balance the following redox equation using the half-reaction method:
MnO4¹ + C204² ⇒ Mn²+ + CO2 (acidic medium)
O
2+
reduction half reachon: Mnoy →Mn²+
Oxidation half reaction: C₂O4 → CO₂
2+
MnOy² + 8H¹+Se¯ →→Mn²+ + 4/₂0
1₂2
(MnOy² +8H*Se →Mn²+ + 4H₂0) x 2
2C₂04² 200₂ +Se
(C₂04²2 CO₂ + ze) xs
Now combine the two half-reactions
2-
2 MnOy² + 5C₂04²² +1GH+ → 2 Mn²+ +10 CO₂ + 8H₂0
LFOON
HOKO
4. Using the balanced redox equation from question #3, answer the following:
A] A student standardized 36.77 mL of a potassium permanganate solution. They used
0.222 grams of sodium oxalate, Na2C2O4. What is the M (molarity) of the KMnO4
solution? Molarity = moles 2 MnO4 + SC₂0₂² +1GH+ 2M₁²+ +1000₂ +8H₂0
"y
2-
volume(L)
196
10
B] How many mL of a standard 0.250 M KMnO4 solution are required to react with 1.0
gram of sodium oxalate, Na2C2O4?
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