A solid object is shaped like the letter A. As in the figure below, it is resting on its side. It is attached to a hinge at the point labeled P. To place the "A" into an upside-down position you plan to push on it at one of the labelled points 1, 2, or 3 so as to exert a torque that overcomes the torque due to the shape's weight. Assume that you can exert a force of fixed magnitude Fo but that you are free to choose at which point you exert it. For each of the statements below decide if it is correct. The figure is to scale. Points 1 and 2 are equidistant from point P. The line segment connecting 1 and 2 is not vertical. 1 I. If you can exert the force Fo at each point in any direction you choose, then the maximum counterclockwise torque you can exert is greatest at point 3 and equal at points 1 and 2. II. The clockwise torque due to the shape's weight that you have to overcome is largest (in magnitude) when the shape is partway between its initial position lying on its side and its final inverted position. III. With the "A" on its side, as in the figure, if the force Fo applied at each point is vertically up, then the torque you can exert at point 3 is greater than the torque at point 1, which is greater than the torque at point 2. 1=True; II = True; III = False 1=False; II = False; III = True 1=True; II = True; III = True 1=True; II = False; III = True 1=False; II = True; III = True 000

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A solid object is shaped like the letter A. As in the figure
below, it is resting on its side. It is attached to a hinge at the
point labeled P. To place the "A" into an upside-down position
you plan to push on it at one of the labelled points 1, 2, or 3 so
as to exert a torque that overcomes the torque due to the
shape's weight. Assume that you can exert a force of fixed
magnitude Fo but that you are free to choose at which point
you exert it. For each of the statements below decide if it is
correct. The figure is to scale. Points 1 and 2 are equidistant
from point P. The line segment connecting 1 and 2 is not
vertical.
1
I. If you can exert the force Fo at each point in any direction
you choose, then the maximum counterclockwise torque you
can exert is greatest at point 3 and equal at points 1 and 2.
II. The clockwise torque due to the shape's weight that you
have to overcome is largest (in magnitude) when the shape is
partway between its initial position lying on its side and its
final inverted position.
III. With the "A" on its side, as in the figure, if the force Fo
applied at each point is vertically up, then the torque you can
exert at point 3 is greater than the torque at point 1, which is
greater than the torque at point 2.
1=True; II = True; III = False
1=False; II = False; III = True
1=True; II = True; III = True
1=True; II = False; III = True
1=False; II = True; III = True
000
Transcribed Image Text:A solid object is shaped like the letter A. As in the figure below, it is resting on its side. It is attached to a hinge at the point labeled P. To place the "A" into an upside-down position you plan to push on it at one of the labelled points 1, 2, or 3 so as to exert a torque that overcomes the torque due to the shape's weight. Assume that you can exert a force of fixed magnitude Fo but that you are free to choose at which point you exert it. For each of the statements below decide if it is correct. The figure is to scale. Points 1 and 2 are equidistant from point P. The line segment connecting 1 and 2 is not vertical. 1 I. If you can exert the force Fo at each point in any direction you choose, then the maximum counterclockwise torque you can exert is greatest at point 3 and equal at points 1 and 2. II. The clockwise torque due to the shape's weight that you have to overcome is largest (in magnitude) when the shape is partway between its initial position lying on its side and its final inverted position. III. With the "A" on its side, as in the figure, if the force Fo applied at each point is vertically up, then the torque you can exert at point 3 is greater than the torque at point 1, which is greater than the torque at point 2. 1=True; II = True; III = False 1=False; II = False; III = True 1=True; II = True; III = True 1=True; II = False; III = True 1=False; II = True; III = True 000
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