A sofa manufacturer is interested in the sales their chain of stores. They draw a random sample of 75 stores in the chain, and measure the average daily sales. They find that x = $5 670 and s = $ 1 750 . The 90% confidence interval for the mean sales of their stores is closest to a. ($5410.9 , $5929.1)  b. ($5337.6 , $6002.4)  c. ($5149.5 , $6190.5)  d. ($2791.3 , $8548.8)

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: Of 500 random people surveyed, 72 were smokers.  Find the 95% confidence interval. SE=0.0157

A:

Q: The administration at Warmfuzzy University gave a 7-item questionnaire to a representative sample of…

A: N is the total number of observations.∑X is the summation of the total observations.

Q: In a survey of 3084 adults aged 57 through 85 years it was found that 81.9% of them used at least…

A: Given : Sample Size, n = 3084 confidence level,c=0.9 Significance level, α…

Q: A study is conducted with a group of dieters to see if the number of grams of fat each consumes per…

A: The given data is as follows: Fat Grams XCholesterol Level…

Q: A random sample of 600 adults in Flagstaff found 90 adults who had lost a job in the past year. Find…

A: Step 1:Given data : Sample size n=600no. of successes x=90   Sample proportion p^​=60090​=0.15Let p…

Q: It has long been accepted by the general public that normal body temperature is 98.6 degrees. A…

A:

Q: find the margin of error of a 99% confidence interval for the mean score of all student

A: It is given that  Sample mean = 93 Sample standard deviation, s = 7 Sample size, n = 30

Q: For a confidence level of 80% with a sample size of 24, find the t-score.

A: From the provided information, Confidence level = 80% Level of significance (α) = 1 – 0.80 = 0.20…

Q: The following data are the score of 24 students in Midterm Examination. Find the 67th percentile. If…

A: From given data we have :

Q: Spending on concessions at the movies varies by age of the movie goer. A random sample of 100 adults…

A: It is given that the random sample of 100 adults, 70 purchased popcorn in their 40’s. Another sample…

Q: Beth wants to determine a 90% confidence interval for the proportion of high school students in a…

A: We have given that,  Population proportion (p) = 0.57, margin of error (E) = 0.04 and confidence…

Q: If 1850, 1970 is a confidence interval for a population mean. Find the value of the point estimator…

A:

Q: A health magazine is interested in knowing the population proportion of people who eat fast food…

A:

Q: The National School Lunch Program took a random sample of students who ordered school lunch. Use the…

A: The given data is as follows:Fruit JuiceChocolate MilkTotalCheese Pizza33%55%Chicken…

Q: If r = 0.7 for the probability and statistics course grades of 30 students, construct a 95%…

A: Confidence interval for correlation coefficient is given by,

Q: A history teacher records the SAT scores of all 87 of her students. The data is used to construct a…

A: For calculating the confidence interval, we need to satisfy the following conditions: Independence…

Q: A magazine article reported on Springfield School District's magnet school programs. The article…

A:

Q: Determine if you should use a confidence interval for the mean or a confidence interval for…

A: The aim is to determine whether to use confidence interval for mean or a confidence interval for the…

Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82

A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: A nurse practitioner is studying the effects of sugary drinks on weight gain. To begin the study,…

A: Let us suppose the sample size equals n = 100 From the give relative frequency histogram we have the…

Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75

A: The Confidence Interval formula is X  ±  Z s √(n) Where: X is the mean Z is the Z-value…

Q: Find the confidence level if the n = 32 and xřight = 50.89. %3D

A: Given information- Sample size n = 32 We have given the value χright2=50.89 We have to find the…

Q: How large is the sample if the confidence level is 97%, Ɛ = 2.5%  and ρ = .35?

A:

Q: Here are summary statistics for randomly selected weights of newborn girls: n = 250, x= 32.4 hg, s=…

A: The following information has been provided: The sample size is n=20. The sample mean is x¯=32.5.…

Q: er of yes answers on a questionnaire called the Hooked on ne Checklist (HONC). Of teenagers who had…

A: Sample sizes n1=141 ,n2=178Sample means x1=3.8 ,x2=2.4

Q: . A survey of folk music fans yields this 95% confidence interval estimate of the proportion of fans…

A: The 95% confidence interval for proportion of fans who love music of David Wilcox is 0.74 to 0.86

Q: Given a data set with H = 152.8 and o = 12.4 , calculate the z-score for each of the data points…

A: According to the given information in this question We need to answer rest two because three are…

Q: A social science professor wants to determine if the amount of time that a student, who is in a…

A: Since you have posted question with multiple subparts,we will solve first three subparts for you.To…

Q: According to a Mobile Marketing Company's survey of 2000 people, 60% said that they use their mobile…

A: We have to find nom of successes in given sample.

Q: The County Development Agency does a survey of all the mobile home manufacturers in Clarion County…

A:

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: Scott wants to find a 95% confidence interval for the average GPA for Allegany College of Maryland…

A:

Q: What is the mode for this data set

A: The data that has the highest frequency is called mode. In other words, it is the most frequent…

Q: A statistics tutor wants to assess whether her tutoring has improved her students’ grades. She…

A: Following table shows the calculation for difference, its mean and standard deviation:

Q: The accounting department of Plank Inc. has been asked to estimate the average salaries of its…

A: We have given that Salaries in thousands of US$ are 2298 2470 2407 2548 2099

Q: If 330, 610] is a confidence interval for the population mean. Find the value of the point estimator…

A: The confidence interval for population mean is given by (330, 610) Let M be the sample mean and E be…

Q: Alan wants to estimate the proportion of adults who walk to work. In a survey of 10 adults, he finds…

A: Given: Alan wants to estimate the proportion of adults who walk to work. Total number of adults=10…

Q: If [1740, 1850] is a confidence interval for a population mean. Find the margin of error. Select…

A:

Q: Find the confidence level and α for an 80​% confidence interval.

A: Given confidence level =80%

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.