A small box of mass m, moving at speed v, slides on top of a larger box of mass M which rests on the frictionless ground. The coefficient of kinetic friction between the large box and the small box is µ. Assuming the large box is wide enough to keep the small box from falling off, the interaction between these two boxes will bring them both to the same final speed vf.
A small box of mass m, moving at speed v, slides on top of a larger box of mass M which rests on the frictionless ground. The coefficient of kinetic friction between the large box and the small box is µ. Assuming the large box is wide enough to keep the small box from falling off, the interaction between these two boxes will bring them both to the same final speed vf.
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A small box of mass m, moving at speed v, slides on top of a larger box of mass M which rests on the
frictionless ground. The coefficient of kinetic friction between the large box and the small box is µ. Assuming
the large box is wide enough to keep the small box from falling off, the interaction between these two boxes
will bring them both to the same final speed vf.
(a) Find vf.
(b) How long does it take for both boxes to reach speed vf? Does your answer depend on u? Why or why
not?
(c) Find the minimum width w of the large box that allows the small box to stay on top without falling
off. Here you may neglect the size of the small box.
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Follow-up Question
In last part the value of v_f is wrong. In the numerator the mass should be small m not capital M.
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