A skydiver, who weighs 687 N, is falling at a constant speed with his parachute open. Consider the apparatus that connects the parachute to the skydiver to be part of the parachute. The parachute pulls upward on the skydiver with a force of 620 N. Find the magnitude of the force on the skydiver due to the air.         Needs Complete typed solution with 100 % accuracy.

Q: A block of mass M is suspended at rest by two strings attached to walls, as shown in the figure. The…

A: Given: The object is at rest. The tension T1 = 41 N and θ=41°.

Q: A block with a mass of 6.47 kg is on a horizontal surface that has friction. A string is pulling…

A:

Q: force F2=15.1N acting at an angle of 0 to the horizontal are applied to a block of mass m=2.6kg. The…

A:

Q: A horizontal force of 90.2 N is applied to a 28.5 kg crate on a rough, level surface. If the crate…

A:

Q: A horizontal force of magnitude F = 57.5 N pushes on a block of mass m = 4.7 kg. The block is on a…

A: The given situation can be represented as

Q: A horizontal force of 88.2 N is applied to a 30.5 kg crate on a rough, level surface. If the crate…

A: Here, the net force, Fnet = 88.2NMass of the crate, m = 30.5kgAcceleration of the crate, a = 1.08…

Q: A 620 kg car pulling a 495 kg trailer accelerates forward at a rate of 2.20 m/s2. Assume frictional…

A: Newton's second law of motion states that the acceleration of an object is directly proportional to…

Q: A semi is traveling down the highway at a velocity of v = 27.5 m/s. The driver observes a wreck…

A: The frictional force due to kinetic friction is given by Ff = μkN, where μk = coefficient of kinetic…

Q: A robot pushes a 20-kg giftbox on the horizontal surface as part of the moving job for the holiday…

A: Given term  Mass of giftbox ( m ) = 20 kg  Acceleration due to gravity ( g )  = 10 m/s μs = 0.75 μk…

Q: A man wants to move a heavy wooden crate (82 kg) across a wooden floor.  However, since he is taller…

A:

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”