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A single-line diagram of a planned network is shown in Figure B1, and component parameters given in Table B1. Motor M1 takes an electrical input power of 2 MW from a supply voltage of 11 kV. The fault level capacity of motor M1 is 10 MVA. Calculate: (i) (ii) The corresponding reactances using a common base of 5 MVA and draw a per-unit reactance diagram, showing the location of the fault. The fault level and fault current which would flow into a three-phase symmetrical short circuit fault at the 11 kV busbar. Component Generator G1 Generator G2 Transformer T1 Rating or Length 12.9 MW, 0.86 pf 8.5 MW, 0.85 pf Voltage 6.6 kV Reactance XG1 = 0.1 pu 6.6 kV XG2 = 0.16 pu 25 MVA 6.6/66 kV XT1 = 0.08 pu Transformer T2 Transformer T3 25 MVA 12.5 MVA 66/11 kV XT2 = 0.2 pu 11/0.4 kV XT3 = 0.2 pu Motor M1 2 MW, 0.89 pf, eff=83% 11 kV XM1 = 0.25 pu Line L1 12 km 66 kV 0.9 Q/phase/km Table B1

A single-line diagram of a planned network is shown in Figure B1, and component parameters given in Table B1. Motor M1 takes an electrical input power of 2 MW from a supply voltage of 11 kV. The fault level capacity of motor M1 is 10 MVA. Calculate: (i) (ii) The corresponding reactances using a common base of 5 MVA and draw a per-unit reactance diagram, showing the location of the fault. The fault level and fault current which would flow into a three-phase symmetrical short circuit fault at the 11 kV busbar. Component Generator G1 Generator G2 Transformer T1 Rating or Length 12.9 MW, 0.86 pf 8.5 MW, 0.85 pf Voltage 6.6 kV Reactance XG1 = 0.1 pu 6.6 kV XG2 = 0.16 pu 25 MVA 6.6/66 kV XT1 = 0.08 pu Transformer T2 Transformer T3 25 MVA 12.5 MVA 66/11 kV XT2 = 0.2 pu 11/0.4 kV XT3 = 0.2 pu Motor M1 2 MW, 0.89 pf, eff=83% 11 kV XM1 = 0.25 pu Line L1 12 km 66 kV 0.9 Q/phase/km Table B1

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A single-line diagram of a planned network is shown in Figure B1, and component parameters given in Table B1. Motor M1 takes an electrical input power of 2 MW from a supply voltage of 11 kV. The fault level capacity of motor M1 is 10 MVA. Calculate: (i) (ii) The corresponding reactances using a common base of 5 MVA and draw a per-unit reactance diagram, showing the location of the fault. The fault level and fault current which would flow into a three-phase symmetrical short circuit fault at the 11 kV busbar.
Transcribed Image Text:A single-line diagram of a planned network is shown in Figure B1, and component parameters given in Table B1. Motor M1 takes an electrical input power of 2 MW from a supply voltage of 11 kV. The fault level capacity of motor M1 is 10 MVA. Calculate: (i) (ii) The corresponding reactances using a common base of 5 MVA and draw a per-unit reactance diagram, showing the location of the fault. The fault level and fault current which would flow into a three-phase symmetrical short circuit fault at the 11 kV busbar.
Component Generator G1 Generator G2 Transformer T1 Rating or Length 12.9 MW, 0.86 pf 8.5 MW, 0.85 pf Voltage 6.6 kV Reactance XG1 = 0.1 pu 6.6 kV XG2 = 0.16 pu 25 MVA 6.6/66 kV XT1 = 0.08 pu Transformer T2 Transformer T3 25 MVA 12.5 MVA 66/11 kV XT2 = 0.2 pu 11/0.4 kV XT3 = 0.2 pu Motor M1 2 MW, 0.89 pf, eff=83% 11 kV XM1 = 0.25 pu Line L1 12 km 66 kV 0.9 Q/phase/km Table B1
Transcribed Image Text:Component Generator G1 Generator G2 Transformer T1 Rating or Length 12.9 MW, 0.86 pf 8.5 MW, 0.85 pf Voltage 6.6 kV Reactance XG1 = 0.1 pu 6.6 kV XG2 = 0.16 pu 25 MVA 6.6/66 kV XT1 = 0.08 pu Transformer T2 Transformer T3 25 MVA 12.5 MVA 66/11 kV XT2 = 0.2 pu 11/0.4 kV XT3 = 0.2 pu Motor M1 2 MW, 0.89 pf, eff=83% 11 kV XM1 = 0.25 pu Line L1 12 km 66 kV 0.9 Q/phase/km Table B1
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