A simply supported beam with spans of LAB = 5 ft and LBC = 15 ft supports loads of w = 7.5 kips/ft and P = 28 kips. The cross-sectional dimensions of the wide-flange shape are b = 7.0 in., t₁ = 0.55 in., d = 29.2 in., and t = 0.46 in. Determine the magnitude of: (a) the maximum horizontal shear stress in the beam. (b) the maximum bending stress in the beam. A LAB Answer: (a) Tmax= (b) gmax= i B W LBC ksi ksi bf y

A simply supported beam with spans of LAB = 5 ft and LBC = 15 ft supports loads of w = 7.5 kips/ft and P = 28 kips. The cross-sectional dimensions of the wide-flange shape are b = 7.0 in., t₁ = 0.55 in., d = 29.2 in., and t = 0.46 in. Determine the magnitude of: (a) the maximum horizontal shear stress in the beam. (b) the maximum bending stress in the beam. A LAB Answer: (a) Tmax= (b) gmax= i B W LBC ksi ksi bf y

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Members with compression and bending

Compression members are structural elements that carry compressive axial force. They are the vertical members of a building that support beams and their design, which is governed by buckling and strength. Columns are known as struct or compression members, which are subjected to compressive forces. These members provide stiffness to the building and avoid any imperfection regarding the transfer of axial load. For instance, webs in a truss, braces in a framed structure, tiers, and so on.

Question

A simply supported beam with spans of LAB = 5 ft and LBC = 15 ft supports loads of w = 7.5 kips/ft and P = 28 kips. The cross-sectional
dimensions of the wide-flange shape are b = 7.0 in., t₁ = 0.55 in., d = 29.2 in., and t = 0.46 in. Determine the magnitude of:
(a) the maximum horizontal shear stress in the beam.
(b) the maximum bending stress in the beam.
A
LAB
Answer:
(a) Tmax=
(b) gmax= i
B
W
LBC
ksi
ksi
bf
y

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Step 1: Given Data

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Step 2: Support reaction

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Step 3: Shear force calculation

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Step 4: Moment calculation

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Step 5: Moment of Inertia

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Step 6: a. Maximum horizontal shear stress

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Step 7: b. Maximum bending stress

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