A simple random sample of size n is drawn. The sample mean, x, is found to be 19.1, and the sample standard deviation, s, is found to be 4.8.Click the icon to view the table of areas under the t-distribution.(a) Construct a 95% confidence interval about µ if the sample size, n, is 35Lower bound: Upper bound:(Use ascending order. Round to two decimal places as needed.)44 Table of t-Distribution Areasdf1 1.0002345670.2540.20Area inright tail1.3760.816 1.0610.765 0.9780.7410.9410.727 0.9200.718 0.906071108060.151.9631.3861.2501.1901.1561.13411100.100.053.0781.8861.638 2.3531.5332.1321.476 2.0151.4401415Table VI1.9431.805t-DistributionArea in Right Tail0.0250.026.314 12.7062.920 4.303 4.8493.1822.7762.5712.4472.3650.010.00515.894 31.821 63.6576.965 9.9253.482 4.541 5.8412.9993.747 4.6042.7573.3654.0322.612251743.1432.0083.7072.4000.00250.001127.321 318.30914.08922.3277.45310.2155.5987.1734.7735.8934.31740205.20847850.0005636.61931.59912.9248.6106.8695.9595408

Answered: Image /qna-images/answer/e0bd9011-eeb2-4f82-a4c2-91306c0336e9.jpg

Answered: A simple random sample of size n is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

As part of your work for an environmental group, you want to see if the mean amount of waste generated per adult in your community is less than the national average of 5 pounds per day. You take a simple random sample of 23 adults in your community and find that they average 4 pounds with a standard deviation of 1.5 pounds. Suppose you know the amount of waste generated per day follows a normal distribution. Test at .10 significance.Round to the fourthH0H0: HAHA: Test Statistic: P-value: Did something significant happen? Select the Decision Rule: There enough evidence to conclude
Find the critical value to for the confidence level c = 0.80 and sample size n = 15. Click the icon to view the t-distribution table. (Round to the nearest thousandth as needed.)
Calculate the z-score for the largest value and interpret it in terms of standard deviations. Do the same for the smallest value N: 50 Mean:28.766 SE Mean: 0.476 St.Dev: 3.369 Min: 21.300 Q1: 26.375 Median: 29.400 Q3: 31.150 Max: 35.100
Assume that adults have IQ scores that are normally distributed with a mean of 96.2and a standard deviation 20.7. Find the first quartile Q1, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is ___.
Moviegoers The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 47 moviegoers from a large university revealed that the average number of movies seen per person was 9.1. The population standard deviation is 3.2 movies. At the 0.10 level of significance, can it be concluded that this represents a difference from the national average? Part 1 of 5 State the hypotheses and identify the claim with the correct hypothesis. H: u = 8.5 not claim H, : u + 8.5 claim This hypothesis test is a two-tailed test. Part 2 of 5 Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separate them with commas. Critical value(s):-1.645, 1.645 Part: 2 /5 Part 3 of 5 Compute the test value. Always round z score values to at least two decimal places.
on Heip Assume that adults have IQ scores that are normally distributed with a mean of 95.4 and a standard deviation 24.2. Find the first quartile Q1, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is (Type an integer or decimal rounded to one decimal place as needed.) Enter your answer in the answer box & #3 $ 7 8. 9. 3 4 5 < 6
Construct the indicated confidence interval for the population mean u using the t-distribution. Assume the population is normally distributed. c = 0.95, x= 12.1, s=0.71, n= 14 (Round to one decimal place as needed.)
Moviegoers The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period.A random sample of 42 moviegoers from a large university revealed that the average number of movies seen per person was 9.6. The population standard deviation is 3.2 movies. At the 0.10 level of significance, can it be concluded that this represents a difference from the national average? (a)State the hypotheses and identify the claim with the correct hypothesis. (b)Find the critical value(s). (c)Compute the test value. (d)Make the decision. (e)Summarize the results.
Pick a, b, or c
A simple random sample of size n is drawn. The sample mean, x, is found to be 19.2, and the sample standard deviation, s, is found to be 4.2. Click the icon to view the table of areas under the t-distribution. (a) Construct a 95% confidence interval about u if the sample size, n, is 34. Upper bound: (Use ascending order. Round to two decimal places as needed.) Lower bound: (b) Construct a 95% confidence interval about u if the sample size, n, is 51. Lower bound:: Upper bound: (Use ascending order. Round to two decimal places as needed.) How does increasing the sample size affect the margin of error, E? O A. The margin of error decreases. O B. The margin of error does not change. OC. The margin of error increases. (c) Construct a 99% confidence interval about u if the sample size, n, is 34. Lower bound: Upper bound: (Use ascending order. Round to two decimal places as needed.) Compare the results to those obtained in part (a). How does increasing the level of confidence affect the size…
In a random sample of 22 people, the mean commute time to work was 31.1 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 90% confidence interval for the population mean u. What is the margin of error of u?Interpret the results. The confidence interval for the population mean u is (____, _____)
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches

SEE MORE QUESTIONS

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS