A steel pipe company recently developed a new pipe product for a customer. According to specifications, the pipe is supposed to have an average outside diameter of 2.00 inches with a standard deviation equal to 0.10 inch, and the distribution of outside diameters is
A steel pipe company recently developed a new pipe product for a customer. According to specifications, the pipe is supposed to have an average outside diameter of 2.00 inches with a standard deviation equal to 0.10 inch, and the distribution of outside diameters is
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A steel pipe company recently developed a new pipe product for a customer. According to specifications, the pipe is supposed to have an average outside diameter of 2.00 inches with a standard deviation equal to 0.10 inch, and the distribution of outside diameters is to be normally distributed. Before going into full-scale production, the company selected a random sample of 30 sections of pipe from the initial test run, as shown in the accompanying table. Complete parts a and b below.

Transcribed Image Text:A steel pipe company recently developed a new pipe product for a customer. According to specifications, the pipe is supposed to have an average outside diameter of
2.00 inches with a standard deviation equal to 0.10 inch, and the distribution of outside diameters is to be normally distributed. Before going into full-scale production, the
company selected a random sample of 30 sections of pipe from the initial test run, as shown in the accompanying table. Complete parts a and b below.
E Click the icon to view the data table.
O B. Ho: µ+2.00
HA: H= 2.00
C. Ho: The pipe diameter is normally distributed with u= 2.00 and o = 0.10.
HA: The pipe diameter is not normally distributed with u = 2.00 and o = 0.10.
O D. Ho: The pipe diameter is not normally distributed with u =2.00 and o = 0.10.
HA: The pipe diameter is normally distributed with u = 2.00 and o = 0.10.
Find the observed frequency of each class.
Observed
Class
Frequency
Under 1.9
3
1.9 to under 2.0
14
2.0 to under 2.1
8
2.1 and over
The test statistic is x
(Round to three decimal places as needed.)

Transcribed Image Text:i Data Table
Full data set
Diameter
Diameter
Pipe Section (inches)
Pipe Section (inches)
1
2.03
16
1.96
2
2.14
17
1.88
3
2.07
18
1.99
4
1.99
19
2.14
5
1.91
20
1.91
2.07
21
1.91
7
2.19
22
1.96
8
2.02
23
2.18
9
2.05
24
1.94
10
1.99
25
1.93
11
1.94
26
2.08
12
1.91
27
1.82
13
2.09
28
1.94
14
2.03
29
1.96
15
2.11
30
1.81
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