5 Exercise 08.02 Algo (Population Mean: Sigma Known)OA simple random sample of 90 items from a population with o = 9 resulted in a sample mean of 35.If required, round your answers to two decimal places.a. Provide a 90% confidence interval for the population mean.tob. Provide a 95% confidence interval for the population mean.toc. Provide a 99% confidence interval for the population mean.to◄ Question 2 of 2Hint(s) Check My WorkHint(s) Check My Work

The population standard deviation is given as, σ=9. For the considered 90 sampled items (i.e.,…

Answered: A simple random sample of 90 items from…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In the past, the mean age of consumers of a product was 38 years. Recently the product has been drastically changed. In order to determine whether there has been a change in the mean age of the product consumers, a sample of 16 consumers is selected. The mean age in the sample is 33 years and the standard deviation in the sample is 10 years. Let u = the mean age of the current product (Problem Set #7) consumers. The value of the test statistic is Oa. -2.00 O b.-1.60 OC .0.8 O d. 4.21
Abe and Betty want to estimate the mean of a population with known standard deviation o. Abe takes 50 samples whereas Betty takes 80 samples. Which of the following statements are correct? (A) If both Abe and Betty use confidence intervals of the same width, then the confidence level of Abe's interval is smaller than that of Betty's (B) If both Abe and Betty use confidence intervals of the same width, then the confidence level of Abe's interval is larger than of Betty's (C) If Abe and Betty construct confidence intervals with the same confidence level, then the width of Abe's interval is smaller than that of Betty's (D) If Abe and Betty construct confidence intervals with the same confidence level then the width of Abe's interval is larger than that of Betty's (B) and (C). (A) and (D) (B) and (D) (A) and (C)
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. In a random sample of 400 private high school students, 320 said they brought a smartphone to school that day, while in a random sample of 400 public high school students, 288 said they brought a smartphone to school that day. Which of the following represents a 98 percent confidence interval estimate for the difference (private high school minus public high school) between the proportions of all private high school and public high school students who bring a smartphone to school? (0.8)(0.2) (0.72)(0.28) (A) (0.8-0.72)±1.96, 400 400 (B) (0.8-0.72)±2.054, + (0.8)(0.2) (0.72)(0.28) 400 400 (C) (0.8-0.72)±2.326 + (0.8)(0.2) (0.72)(0.28) 400 400 1 (D) (0.8-0.72)±2.054, (0.76)(0.24) + 400 400 (E) (0.8-0.72)±2.326, (0.76)(0.24) + I 400 400
Last year over 7000 students took an entrance exam at a certain state university. Kareem's score was at the 44th percentile. Lella's score was at the 93rd percentile. (a) Which of the following must be true about Kareem's and Leila's scores? Both Kareem and Leila scored higher than the median. O Both Kareem and Lella scored below than the median. O Leila scored higher than Kareem. O Kareem scored higher than Leila. (b) Which of the following must be true about Kareem's score? O About 44% of the students who took the exam scored lower than Kareem. O Kareem got about 44% of the questions correct. O Kareem's score was in the top half of all scores. O Kareem missed 56 questions. Explanation Check X 3 Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center
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Determine if the following statements are true or false. a. Jane took a sample of n = 100 observations from a population with mean and standard deviation. Mike also took a sample of n = 200 observations from the same population. Then, Mike’s sample mean will be closer to the true population mean than Jane’s sample. b. Jane took a sample of n = 100 observations from a population with mean and standard deviation. Mike also took a sample of n = 200 observations from a population with mean and standard deviation 2. Then, the sample mean from Mike’s sample is more likely to be close to the true mean than the sample mean from Jane’s sample. That is, the probability that X is between 90% and 110% of mean is higher for Mike’s sample than for Jane’s sample.
If [1740, 1850] is a confidence interval for a population mean. Find the value of the point estimator of the population mean. Select one: O a. 1910 O b. 1660 O c. 1540 O d. 1795
ANSWER MUST BE IN WHOLE NUMBER 1. Young researchers wants to estimate the average numbers of students spending their time on watching movies. The standard deviation from a previous study is 4 hours. How large a sample must be selected if they want to be: a. 95% confidence from the sample mean by 3.5 hours? b. 99% confidence from the sample mean by 2.5 hours? c. 99% confidence from the sample mean by 3.5 hours?

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