A simple random sample of 19 models’ runnaway is obtained, providing a standard deviation of 11.19. Construct a 90% confidence interval for σ, the standard deviation from which the sample was obtained
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A simple random sample of 19 models’ runnaway is obtained, providing a standard deviation of 11.19. Construct a 90% confidence interval for σ, the standard deviation from which the sample was obtained.
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- A manufacturer claims that the mean lifetime, u, of its light bulbs is 44 months. The standard deviation of these lifetimes is 7 months. Twenty-three bulbs are selected at random, and their mean lifetime is found to be 48 months. Assume that the population is normally distributed. Can we conclude, at the 0.01 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 44 months? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. p H, :0 H, :0 (b) Determine the type of test statistic to use. (Choose one) v O=0 OSO |(c) Find the value of the test statistic. (Round to three or more decimal places.) OA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 18 subjects had a mean wake time of 101.0 min. After treatment, the 18 subjects had a mean wake time of 97.7 min and a standard deviation of 21.7min. Assume that the 18 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 101.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. ____min<μ<___minA manufacturer claims that the mean lifetime, u, of its light bulbs is 42 months. The standard deviation of these lifetimes is 6 months. Twenty-seven bulbs are selected at random, and their mean lifetime is found to be 41 months. Assume that the population is normally distributed. Can we conclude, at the 0.01 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 42 months? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H1. p H, :0 H, :0 (b) Determine the type of test statistic to use. D=D OSO (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the two critical values. (Round to three or more decimal places.) Dand (e) Can we conclude that the mean lifetime of…A simple random sample of 80 adults is obtained, and each person’s red blood cell count is measured. The sample mean is 6.25 and a standard deviation of .65. Use a .01 significance level to test the claim that the sample is from a population with a mean less than 6.4, which is a value often used for the upper limit of the range of normal values. (For each hypothesis test state H0 and H1)A manufacturer claims that the mean lifetime, u, of its light bulbs is 54 months. The standard deviation of these lifetimes is 6 months. Nineteen bulbs are selected at random, and their mean lifetime is found to be 50 months. Assume that the population is normally distributed. Can we conclude, at the 0.05 level of significance, that the mean lifetime of light bulbs made by this manufacturer differs from 54 months? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H. H, :0 H :0 (b) Determine the type of test statistic to use. (Choose one) ▼ D=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) OA consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television sets. Tube type A has mean brightness of 100 and standard deviation of 16, and tube type B has unknown mean brightness, but the standard deviation is assumed to be identical to that for type A. A random sample of n = 25 tubes of each type is selected, and Xpar B – XbarA is computed. If ug equals or exceeds uA, the manufacturer would like to adopt type B for use. The observed difference is xhar B - Ibar A = 3.5. What decision would you make, and why?A researcher claims that the average life span of mice can be extended when the calories in their diet are reduced by approximately 40% from the time they are weaned. The restricted diets are enriched to normal levels by vitamins and protein. Suppose that a sample of 10 mice is fed a normal diet and has anaverage life span of 32.1 months with a standard deviation of 3.2 months, while a sample of 15 mice is fed the restricted diet and has an average life span of 37.6 months with a standard deviation of 2.8 months. Assume the distributions of life spans for the regular and restricted diets are approximately normal withequal variance.(a) State the appropriate hypotheses to test the researcher’s claim.(b) Conduct the test at the 0.05 level of significance. What do you conclude?2) The manufacturer of a certain brand of automobiles component claims that mean life of these component is 70 months. An independent agency wants to check this claim and took a random sample of 40 components and found that the mean life for this sample is 67 months with a standard deviation of 5 months. At 5% LOS, can we conclude that the mean life of these component is less than 70 months?A health professional obtains records for 33 patients who have undergone a certain surgical procedure and finds the average length of stay is 3.23 days with a standard deviation of 1.58 days. Using α=0.10 is there evidence to suggest the actual average length of stay for this surgical procedure is 3 days? The correct conclusion is that we Select an answer: (can, maybe can, cannot) conclude that the average length of stay of Select an answer: (all, sampled, randomly selected) surgeries of this type Select an answer: (is less than, is is different from, is more than) Select an answer: (3.23, 0.85, 3) days.What level of concern do you have for the validity of your results? 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