A simple pendulum is made of a 50 cm-string and a particle like bob of mass m = 10 g. At t= 0, the pendulum is at its equilibrium position and is given an ini- tial velocity v = + 0.2 m/s as shown. The potential energy has zero reference at the lowest point of the pendulum. Take g = 10 m/s'. %3D 9) The displacement angle corresponding to v = 0.1 m/s is: a. 0 = 0.43 rad %3D b. 0 = 4.44 rad c. 0 = 4.44° d. 0 = 44.4° Va = + 0.2 m/s %3D

A simple pendulum is made of a 50 cm-string and a particle like bob of mass m = 10 g. At t= 0, the pendulum is at its equilibrium position and is given an ini- tial velocity v = + 0.2 m/s as shown. The potential energy has zero reference at the lowest point of the pendulum. Take g = 10 m/s'. %3D 9) The displacement angle corresponding to v = 0.1 m/s is: a. 0 = 0.43 rad %3D b. 0 = 4.44 rad c. 0 = 4.44° d. 0 = 44.4° Va = + 0.2 m/s %3D

Name: A simple pendulum is made of a 50 cm-string and a particle like bob o
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: A simple pendulum is made of a 50 cm-string and a particle like bob of massm 10 g. At t = 0, the pendulum is at its equilibrium position and is given an ini-tial velocity v =+ 0.2 m/s as shown The potential energy has zero reference atthe lowest poi

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

This, the length of the pendulum is 1.89 m. Now you start with the pendulum at 8.5 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 42.5 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it? 4.99 m/s 3.06 m/s 3.12 m/s 0.64 m/s
The bob of a simple pendulum is displaced by an initial angle 0(0) = -Omax/2 and is given an initial velocity in the positive direction. The phase constant, p, of the angular displacement when expressed as a cosine function is: -21/3, O -T/3, +T/3, +2n/3, +T/6, Clear selection
A 1.5-m length pendulum is displaced by an initial angle e = +6° and released from rest. If the angular position is given as a cosine function, E(t) = Omax cos(wt+p), then the angular velocity as a function of time is: (Take g = 10 m/s?) e'(t) = 0.24 sin(2.6t+r/2) O e'(t) = -0.27 sin(2.6t) O e'(t) = -0.24 sin(2.3t+T) e'(t) = -0.27 sin(2.6t+n) O e'(t) = 0.27 sin(2.6t-t/3)
Problem 1. Energy Terms Determine the potential energy of the pendulum shown below. Note: The potential en- ergy should be 0 when 0 = 0, mgL when 0=1, and 2mgL when 0 = 1. /////// 8 m Q Search 99+ H
A simple pendulum with a length of 1.73 m and a mass of 6.74 kg is given an initial speed of 2.36 m/s at its equilibrium position. (a) Assuming it undergoes simple harmonic motion, determine its period (in s). (b) Determine its total energy (in J). (c) Determine its maximum angular displacement (in degrees). (For large v, and/or small /, the small angle approximation may not be good enough here.) (d) What If? Based on your answer to part (c), by what factor would the total energy of the pendulum have to be reduced for its motion to be described as simple harmonic motion using the small angle approximation where 0 ≤ 10°?
A pendulum is undergoing simple harmonic motion. At a particular instant, you measure its speed to be v0,and you notice that exactly half of its energy is potential, and the other half is kinetic. It is a simple pendulum oflength l, with all of its mass (m) concentrated in a point at the end. a) In terms of v0, what is the highest speed the pendulum will reach? b)What is the largest angle that the pendulum will reach?
A block of mass m = 3kg is attached to a lipht spring with a spring constant k and moves in simple harmonic motion on a frictionless horizontal surface. Initially the spring is compressed to xo = -0.1 m from its equilibrium position and is given an initial velocity vo in the negative x-direction, as shown in the figure below. The maximum speed reached by the block is vmax=V2 m/s. The block's period of oscil- lation is T 0.889s. 2) The maximum displacement of the block A is: Eguilibnum a. + 0.2 m b. 0.2 cm c. 0.2 m d.- 0.2 m www m X-- 0Im
Please answer the following question. A point in a machine moves with simple harmonic motion. When this point is 0.8 metre from the mid path, its velocity is 10 m/s and when 1.5 metres from the centre of its path its velocity is 4 m/s. Calculate: 1.1The angular velocity of the point. 1.2. The periodic time of the point. 1.3. The maximum acceleration of the point.
At t = 0, the bob of a simple pendulum is displaced to the right by an angle e_0 = +0_max/√2 and is given an initial velocity to the left (v_0<0). The phase constant, op, of the angular displacement when expressed as a cosine function, 0(t) = 0_max cos (wt + p), is: 4 = +π/3 =-π/3 4 = +π/4 4= -1/4 4=0
A metal sphere with a mass 7.00 kg is connected to a spring with a force constant of 200 N/m, and it oscillates horizontally with an amplitude of 2.20 cm. (a) What is the total mechanical energy (in J) of the sphere-spring system? (b) What is the maximum speed (in m/s) of the oscillating sphere? m/s (c) What is the maximum magnitude of acceleration (in m/s2) of the oscillating sphere? m/s²
A coin having a mass of m = 12 g, a thickness of h = 0.17 cm, and a radius of r = 1.5 cm has a small hole drilled through it so that it can be suspended from a thin wire and worn as an earring or pendant. The hole is at a distance of 7/8 r from the center of the coin as shown above. When suspended from this hole, the coin is a physical pendulum that swings back and forth with this hole as its axis of rotation. Assuming that the hole does not appreciably change the center of mass of the coin, determine the period of this physical pendulum.
Clear selection A simple pendulum is made of a 50 cm-string and a bob of mass m. Att= 0, the pendulum is at its equilibrium position and is given an initial velocity v = 0.1m/s. The maximum angular speed, O'max, is: O 01 rad/s O 0.8 rad/s 0,4 rad/s O 0.2 rad/s 0.05 rad/s Page 2 of 2 Back Submit