A simple curve of the proposed extension ofMantabahadra Highway have a direction of tangent ABwhich is due north and tangent BC bearing N.50°E. Point Ais the PC whose stationing is 20+130.46. The degree ofcurve is 4°.• Determine the angle of intersection.Determine the radius of the curve in meters usingarc basis.• Determine the tangent distance in meters.• Determine the external distance in meters from themidpoint of the curve up to the point of intersectionof two tangents.• Determine the middle ordinate of the curve inmeters.• Determine the length of curve in meters.• Determine the length of cord in meters.• Determine the station Pl.• Determine the station PT.

Answered: Image /qna-images/answer/0409a727-3c1c-43eb-ba03-32305ed78c01.jpg

Answered: A simple curve of the proposed…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Two tangents that intersect at an angle of 44deg 36’ are to be connected by a compound curve. The tangent at the beginning of the curve at the P.C. is 125.70 m long and that at the P.T. is 155.6 m long. The degree of curvature of the first curve at P.C. is 4deg. Using Arc basis, Determine the radius of the first curve. 286.479 m 150.58 m 322.62 m 445.42 m
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The tangents of a simple curve have bearings of N20°E and N80°E respectively. The radius of curvature is 200.Compute the following:A. Length of the long chordB. Length of the curveC. Degree of the curve SHOW A CLEAR SOLUTION.
Point A is the point of intersection of the tangents. Two tangents AB and AC are connected bya compound curve. Angle ABC is 30 degrees and angle ACB is 40 degrees. Distance BC is 200mand the radius of the second curve is 100m. Determine the central angle of the first curve.
Probiem A simple curve connects two tangents AB and BC with bearings N 75012' E and S 78036' E, respectively. If the stationing of P.C. is 10+185.28. and its middle ordinate is 7.46 m, Determine the following a. Radius of the curve b. Tangent Distance External Distance d. iong Chord e. Length of the curve. Stationing of the vertex g. Degree of the curve using Arc Basis
The intersection of two proposed tangent AB and CD are inaccessible. From point G which is at Sta 10+266 on Tingent All The line GH is run to the point Fonn the Tangent CD The angle between the prolongation of AB and the line GH as measured by the transit is found to be 37 degrees. The line GHK measured and found to be 134.50 m and the angle between GH and the prolongation of CD is 24 degrees. It Tangent AB and CD are to be connected by 5 degrees. Find the STA of PC.
Curve, highway.
Q#02: Two tangents intersect at chainage 4100 m. Ø 35 35 35". Carry out all the data necessary for setting out the curve, with R = 1000 m and Peg interval being 15 m by: 1) By deflection angle 2) By offsets from chords produced 3) By offset from tangent (Both cases)
A simple curve of the proposed extension of Mantabahadra Highway have a direction of tangent AB which is due north and tangent BC bearing N45°E. Point A is at the P.C. who stationing is 20 + 130.46. The degree of the curve is 4º. 1.1. Compute the long chord of the curve 1.2. Compute the stationing at point D on the curve along a line joining the center of the curve which makes an angle of 54° with the tangent line passing thru the P.C. 1.3. What is the length of the line from D to the intersection of the tangent AB.
The offset distance of the simple curve from PT to the tangent line passing through the PC is equal to 120.20m. The stationing of PC is at 2 + 540.26. The simple curve has an angle of intersection of 50° a. Compute the degree of curve. b. Compute the external distance. c. Compute the length of long chord.
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1. From a known point V (vertex), the tangent lines of a compound curve are drawn - having azimuths 300 (forward tangent) and bearing N 04 E (back tangent), respectively. A common tangent line CD intersects the two tangent lines at bearing S 34° E. Stationing of the vertex of the compound curve is 16+ 464.35 and the distance from point D to the vertex of the compound curve is 137.6 m. If the external distance of the curve passing through the PC is 1.42 times the external distance of the simple curve that passes through the PT, solve for the following. a. Radius of the curve that passes through the PC b. Radius of the curve that passes through the PT c. Stationing of the PT

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