A simple circular curve connects two straights (AB & BC) intersected at point B, Station 2+000. If the azimuth of line BC is 120° and the coordinates of PC and B are (100, 100) m and (200, 200) m respectively. Determine: Degree of the Curve (use Arc Basis) Angle of Intersection Point of curvature PC Station 2 + Point of tangency PT Station 2 + Tangent (PC to Pl or PI to PT) T Radius of simple curve R m Length of chord from PC to PT L. Length of curve from PC to PT Lc m External distance E Middle ordinate or mid ordinate m m
A simple circular curve connects two straights (AB & BC) intersected at point B, Station 2+000. If the azimuth of line BC is 120° and the coordinates of PC and B are (100, 100) m and (200, 200) m respectively. Determine: Degree of the Curve (use Arc Basis) Angle of Intersection Point of curvature PC Station 2 + Point of tangency PT Station 2 + Tangent (PC to Pl or PI to PT) T Radius of simple curve R m Length of chord from PC to PT L. Length of curve from PC to PT Lc m External distance E Middle ordinate or mid ordinate m m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![A simple circular curve connects two straights (AB & BC) intersected at point B, Station 2+000. If the azimuth of line BC is 120° and the coordinates of PC and B are (100, 100) m and (200, 200) m
respectively. Determine:
Degree of the Curve (use Arc Basis)
Angle of Intersection
Point of curvature
PC
Station 2 +
Point of tangency
PT
Station 2 +
Tangent (PC to Pl or PI to PT)
Radius of simple curve
m
Length of chord from PC to PT
m
Length of curve from PC to PT
Lc
External distance
E
Middle ordinate or mid ordinate
m
m
E
E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ee648c0-d111-4cb5-80de-9e704a06a691%2F27652bc9-eb5e-4640-b39c-1b3dd28644c9%2F4b8wya_processed.png&w=3840&q=75)
Transcribed Image Text:A simple circular curve connects two straights (AB & BC) intersected at point B, Station 2+000. If the azimuth of line BC is 120° and the coordinates of PC and B are (100, 100) m and (200, 200) m
respectively. Determine:
Degree of the Curve (use Arc Basis)
Angle of Intersection
Point of curvature
PC
Station 2 +
Point of tangency
PT
Station 2 +
Tangent (PC to Pl or PI to PT)
Radius of simple curve
m
Length of chord from PC to PT
m
Length of curve from PC to PT
Lc
External distance
E
Middle ordinate or mid ordinate
m
m
E
E
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