A sequential search of a sorted list can halt when the target is less than a given element in the list. Define a modified version of this algorithm and state the computational complexity, using big-O notation, of its best-, worst-, and average- case performances. Using this template in python: def sequential_search(input_list, target): target_index = -1 #TODO: Your work here # Return target_index. If not found, -1 return target_index if __name__ == "__main__": my_list = [1, 2, 3, 4, 5] print(sequential_search(my_list, 3)) # Correct Output: 2 print(sequential_search(my_list, 0)) # Correct Output: -1

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter18: Stacks And Queues
Section: Chapter Questions
Problem 16PE: The implementation of a queue in an array, as given in this chapter, uses the variable count to...
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A sequential search of a sorted list can halt when the target is less than a given
element in the list. Define a modified version of this algorithm and state the
computational complexity, using big-O notation, of its best-, worst-, and average-
case performances.

Using this template in python:

def sequential_search(input_list, target):
target_index = -1
#TODO: Your work here
# Return target_index. If not found, -1
return target_index
if __name__ == "__main__":
my_list = [1, 2, 3, 4, 5]
print(sequential_search(my_list, 3)) # Correct Output: 2
print(sequential_search(my_list, 0)) # Correct Output: -1

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