A second degree process with time delay is controlled by a closed loop control system with feedback. Using the transfer functions given below, derive the transfer function of the closed-loop system for the disruptive effect. P Determine the Kc values that ensure the stable operation of the control system when the controller is used. Gp(s) 5e-2s (2s + 1)(3s +1) F3-22 Ga(s) = 5+1 G₂(s)=G,(s) = 1
A second degree process with time delay is controlled by a closed loop control system with feedback. Using the transfer functions given below, derive the transfer function of the closed-loop system for the disruptive effect. P Determine the Kc values that ensure the stable operation of the control system when the controller is used. Gp(s) 5e-2s (2s + 1)(3s +1) F3-22 Ga(s) = 5+1 G₂(s)=G,(s) = 1
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:A second degree process with time delay is controlled by a closed loop control system
with feedback. Using the transfer functions given below, derive the transfer function of
the closed-loop system for the disruptive effect. P Determine the Kc values that ensure
the stable operation of the control system when the controller is used.
Gp (s):
5e-2s
(2s + 1)(3s +1)
F3-22
Ga(s)
1
s+1
G₂(S) = G,(s) = 1
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![21:33 d
←
G₁P =
Dissruptive effect.
Now ,
50-25
(25 41) (3541)
Cont sruller
Step3
c)
G (s) =
with
Charactresti oyun
ITC
(25+1)(3541)
0-3k(70
+
07(s):
115²
:
⇒ 65² +65³ +55+ 55²
= 65³
(2541) (35-1) (les) +
(65² +55 +1) (1+8)
+
+
Gd (s)
Gid
1+ GC GUGP
i t
(25+1)(3541)
(541) ( (25+1) (95-1) +60-45)
1 +
51TC
-
tlust
S+1
5 Kcs
5e
(2541) (3541)
-25
65
=) 65³ + 115² + s (6-5k) +
5 e²s (11) 20
(2541) (3541)
1-S
1
S+1
5 kc (1-st
145
5 K
f
{]
SKIS 20
ل:
-d
- SIXCS
5K(+1=0
5 KG 1-d
√x
Vo
LTE
4.5G
59
Do](https://content.bartleby.com/qna-images/question/39148a35-4429-4081-bda7-45987e59e1e2/fda67216-1abe-40e7-b009-339d7e436873/c26hagq_processed.jpeg)
Transcribed Image Text:21:33 d
←
G₁P =
Dissruptive effect.
Now ,
50-25
(25 41) (3541)
Cont sruller
Step3
c)
G (s) =
with
Charactresti oyun
ITC
(25+1)(3541)
0-3k(70
+
07(s):
115²
:
⇒ 65² +65³ +55+ 55²
= 65³
(2541) (35-1) (les) +
(65² +55 +1) (1+8)
+
+
Gd (s)
Gid
1+ GC GUGP
i t
(25+1)(3541)
(541) ( (25+1) (95-1) +60-45)
1 +
51TC
-
tlust
S+1
5 Kcs
5e
(2541) (3541)
-25
65
=) 65³ + 115² + s (6-5k) +
5 e²s (11) 20
(2541) (3541)
1-S
1
S+1
5 kc (1-st
145
5 K
f
{]
SKIS 20
ل:
-d
- SIXCS
5K(+1=0
5 KG 1-d
√x
Vo
LTE
4.5G
59
Do
Solution
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