A scientist plans to test Ho : u = µo versus HA : u 7 µo using n47 observations and setting the significance level to 2.5%. Find therejection region for this experiment.a. Reject the null hypothesis if the absolute value of T =s/Vis larger than 2.0129b. Reject the null hypothesis if T = is larger than 2.0129X-%3Dc. Reject the null hypothesis if T = 40 is smaller than -2.01298/Vnd. Reject the null hypothesis if the absolute value of T = is larger than 2.3172e. Reject the null hypothesis if T =A is larger than 2.3172Xpof. Reject the null hypothesis if T = 4 is smaller than -2.3172

Answered: Image /qna-images/answer/caae6224-76f6-4c0a-9889-ab9ae988f841.jpg

Answered: A scientist plans to test Ho : H= µ0…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You want to see if the percentage of cat owners is significantly different than the percentage of dog owners at a significance level of α=0.05.You sample 223 people and find 110 have cats. You sample an additional 627 people and find 231 have dogs.What is the critical value for this test? (Report answer accurate to three decimal places.)critical value = ±±What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic =
Use the calculator displays to the right to make a decision to reject or fail to reject the null hypothesis at a significance level of α=0.05. Z-Test Z-Test Inpt: Data Stats μ≠50 μ0:50 z=−1.40859042 σ:5.25 p=0.15895631 x:48.75 x=48.75 n:35 n=35 μ: ≠μ0 <μ0 >μ0 Calculate Draw Choose the correct answer below. A. Since the P-value is greater than α, reject the null hypothesis. B. Since the P-value is less than α, reject the null hypothesis. C. Since the P-value is less than α, fail to reject the null hypothesis. D. Since the P-value is greater than α, fail to reject the null hypothesis.
You wish to test Ho: M₁ = μ₂ versus Ha:μ₁ < μµ₂ at a = 0.01. You obtain a sample of size n₁ = 12 = with a mean of 1 82.7 and a standard deviation of $1 sample of size n₂ = 9 with a mean of 2 = 84.9 and a standard deviation of $2 population. Assume that the populations are normal with equal variances. 14.2 from the first population. You obtain a = © 20.1 from the second Do not round interim calculations. Round your final answers to three decimal places. (a). Find the test statistic: (b). Using your answer from (a), find the p-value: = (c). You Select an answer the null hypothesis. (d). There is Select an answer evidence to conclude the first population mean is less than the second population mean
A study of road rage asked random samples of 596 men and 523 women about their behavior while driving. Based on their answers, each person was assigned a road rage score on a scale of 0 to 20. The participants were chosen by random digit dialing of phone numbers. The researchers performed a test of the following hypotheses: Ho: μM=μF versus Ha: μM≠μF.Ho: μM=μF versus Ha: μM=μF. The P-value for the stated hypotheses is 0.002. Interpret this value in the context of this study. A) Assuming that the true mean road rage score is the same for males and females, there is a 0.002 probability of getting a difference in sample means. B) Assuming that the true mean road rage score is the same for males and females, there is a 0.002 probability of getting an observed difference at least as extreme as the observed difference. C) Assuming that the true mean road rage score is different for males and females, there is a 0.002 probability of getting an observed difference at least as…
The police chief selects a sample of 50 local police officers from a population of officers with a mean physical fitness rating of 75 ± 8.0 (m ± s) on a 100-point physical endurance rating scale. He measures a sample mean physical fitness rating on this scale equal to 79. He conducts a one–independent sample z test to determine whether physical endurance increased at a .05 level of significance. Compute effect size using Cohen’s d.
Perform the test of hypotheses indicated, using the data from independent samples given. Use the critical value approach. Compute the p-value of the test, as well. a. Test Ho : µ1 – Hg = 0 vs. Ha : H1 - H2 # 0 @a = 0.01: ni = 125, 1 =-46, 81 = 10 n2 = 90, x 2 = -50, 82 = 13 b. Test Ho : H1 – Hz = 20 vs. Ha : µ1 – H2 > 20@a = 0.05: ni = 40, x1 = 142, s1 = 11 40, x2 = 118, s2 = 10 n2 the ariticalI
Look at the attached photo. There is a normality test for the two groups of INR and PCV. Interpret the data by explaining in details what each result means. Include a brief justification on why the PCR was normal and the INR was not normal.
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= 3 versus Example: In a two sample test of Ho: ₁-2 H₁₁-23, suppose that the data are normal, m = n and o² = 0 = 84.0. Can we choose m such that the test has level a = 0.01 and 3 = 0.05 at 1₁ - ₂ : 5.0? This question concerns experimental design.
Use the calculator displays to the right to make a decision to reject or fail to reject the null hypothesis at a significance level of α=0.05. Z-Test Z-Test Inpt: Data Stats μ≠80 μ0:80 z=−1.41421356 σ:3.75 p=0.15729921 x:79.25 x=79.25 n:50 n=50 μ: ≠μ0 <μ0 >μ0 Calculate Draw Question content area bottom Part 1 Choose the correct answer below. A. Since the P-value is greater than α, fail to reject the null hypothesis. B. Since the P-value is less than α, reject the null hypothesis. C. Since the P-value is greater than α, reject the null hypothesis. D. Since the P-value is less than α, fail to reject the null hypothesis.
Use the calculator displays to the right to make a decision to reject or fail to reject the null hypothesis at a significance level of α=0.10. Z-Test Z-Test Inpt: Data Stats μ≠80 μ0:80 z=−1.18321596 σ:3.75 p=0.23672357 x:79.25 x=79.25 n:35 n=35 μ: ≠μ0 <μ0 >μ0 Calculate Draw Choose the correct answer below. A. Since the P-value is greaterthan α, fail to reject the null hypothesis. B. Since the P-value is lessthan α, reject the null hypothesis. C. Since the P-value is lessthan α, fail to reject the null hypothesis. D. Since the P-value is greaterthan α, reject he null hypothesis.
The NAEP considers that a national average of 283 is an acceptable performance. Using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2019 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2019 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?

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