A schematic of a homemade hydraulic jack is shown in the figure below, with cylindrical tube ends of different radii, 1 = 0.0480 m and r2 = 0.300 m, respectively. (a) If a downward force of F1 = 16.0 N is applied to the end with the smaller radius, how much force F2 would the jack exert on a car if it were sitting above the other end? (Enter the magnitude.) ]N (b) If the smaller piston is pushed down a distance d, = 0.176 m, through what distance d, would the other end move? m

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A: Given, Radius of small tude, r1=0.050 m, Radius of big tude, r2=0.100 m, Force, F1=16 N.

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A: compression in length (∆L) = 2.98×10-5 m Length (L) = 36 cm = 0.36 m Radius (r) = 1.82 cm = 0.0182 m…

Q: A schematic of a homemade hydraulic jack is shown in the figure below, with cylindrical tube ends of…

A:

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Q: A schematic of a homemade hydraulic jack is shown in the figure below, with cylindrical tube ends of…

A: We need to calculate the force F2 and also the distance moved by the larger piston, d2.

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Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.