12. Which choice best describes the value of the appropriate test statistic for this test?(a)F = 1.926(b)F =3.709(c)F = 2.853(d)F(e)F = 0.519=37.092 A sample with 11 observations from population 1 has a sample standard deviation s₁ = 5.2. A samplewith 14 observations from population 2 has a sample standard deviation s2 = 2.7. Both populations areknown to be approximately normal. Consider the following hypotheses:Ho: 0² ≤ 0²/Ha : 0² > 0²/

From the information, given thatThe given hypotheses are,

Answered: A sample with 11 observations from…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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7. On paper. A precision instrument is guaranteed to read accurately to within 2 units. Asample of four instrument readings on the same object yielded the measurements 353, 351, 351, and 355.1. Test the null hypothesis that σ = 0.7 against the alternative σ > 0.7. Use α = 0.05. 2. Find a 90% confidence interval for the population variance.
In a random sample of 29 residents living in major cities on the West Coast (Group 1) and 29 residents living in major cities on the East Coast (Group 2), each individual was asked their age. The results can be seen in the table below. The population standard deviation of the age in West Coast cities is known to be 11.2 years and in East Coast cities is known to be 9.3 years. Assume the populations are normally distributed. Run a test at a 0.05 level of significance to test if west coast cities are, on average, older. West Coast (Group 1) East Coast (Group 2) 25 34 47 45 18 37 38 20 30 19 50 26 52 79 61 46 40 29 22 55 34 23 35 35 55 36 60 51 68 41 20 50 33 32 36 38 37 26 42 44 60 19 71 28 54 27 20 18 45 30 52 20 34 22 57 43 64 62 Enter the P-Value - round to 4 decimal places. Make sure you put…
A gaussian curve states that its average is 452.22 and a standard deviation of 12.5. What would be a proper null Hypothesis for this? Ho 452.22 (the average) Ho 12.5 (the standard deviation) Ho = 464.72 (the average plus the standard deviation) Ho= 439.72 (the average minus the standard deviation)
You wish to test the following claim (HaHa) at a significance level of α=0.005α=0.005. Ho:μ=65.2Ho:μ=65.2 Ha:μ<65.2Ha:μ<65.2You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=101n=101 with mean M=62.6M=62.6 and a standard deviation of SD=7.9SD=7.9.What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
Q10 = In a one-tailed hypothesis test with a sample size of 300, the test statistic is determined to be Z = 1.53 Assuming population standard deviation o is known , The p-value for this test is: Q11 = In a two-tailed hypothesis test with a sample size of 300, the test statistic is determined to be Z = 2.21 . Assuming population standard deviation is known, The p-value for this test is
A sample of size n = 36 is drawn from a population whose standard deviation is σ = 15.6. The sample mean is x = 94.5. Construct a 95% confidence interval.
You wish to test the claim that the average IQ score is less than 100 at the .01 significance level. You determine the hypotheses are: Ho: μ=100 H1:μ<100H You take a simple random sample of 79 individuals and find the mean IQ score is 98.3, with a standard deviation of 15.3. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ score is less…
In order to test the claim that the mean drive speed (Km/hr) of adults in a known highway in a city is at most 75 Km/hr, a sample of 40 adult drivers was taken and resulted a sample mean of 85 Km/hr. If the population standard deviation is 35 Km/hr, perform the test with a level of significance a = 0.05 using the P-value approach. 1. The mull and alternative hypotheses are A. Ho : u 75 and H : u 75 D. Ho : 2 75 and H, : p< 75 2. Test statistic value = (approximate to two decimal places) D. 1.81 A. -1.81 B. 0.29 C. 0.29 3. P-value = A. 0.0702 (approximate to four decimal places) B. 0.1404 C. 0.9298 D. 0.0351 4. The decision of the test: A. Reject Ho, there is a strong evidence that the adults mean drive speed is less than 75 Km/hr. B. Do not reject Ho, there is no evidence that the adults mean drive speed is more than 75 Km/hr. C. Reject Ho, there is a strong evidence that the adults mean drive speed is more than 75 Km/hr. D. Do not reject Ho, there is a strong evidence that the adults…
4. The resilient moduli of 10 samples of a clay mixture are measured and the sample mean is x = 19.50. If an experimenter wishes to use a "known" value o = 1.0 for the standard deviation of the resilient modulus measurements based upon prior experience, construct appropriate 90%, 95%, and 99% two-sided confidence intervals for the average resilient modulus µ. Compare the lengths of the confidence intervals. Do you think it is plausible that the average resilient modulus is equal to 20.0?
Two independent samples have been selected, 7777 observations from population 1 and 5858 observations from population 2. The sample means have been calculated to be ?⎯⎯⎯1=13.4x¯1=13.4 and ?⎯⎯⎯2=11.3x¯2=11.3. From previous experience with these populations, it is known that the variances are ?21=27σ12=27 and ?22=29σ22=29. For the hypothesis test of ?0:(?1−?2)=1.8H0:(μ1−μ2)=1.8 and ??:(?1−?2)≠1.8Ha:(μ1−μ2)≠1.8 Use ?=0.04α=0.04. (a) Compute the test statistic. ?=z= (b) Find the approximate p-value?−?????=p−value= The final conclustion is A. There is not sufficient evidence to reject the null hypothesis that (?1−?2)=1.8(μ1−μ2)=1.8. B. We can reject the null hypothesis that (?1−?2)=1.8(μ1−μ2)=1.8 and accept that (?1−?2)≠1.8(μ1−μ2)≠1.8.
The daily wage of a particular industry is normally distributed with a mean of 150 pesos. In a random sample of 144 workers of a very large company in this industry, the mean daily wage was found to be 148 pesos with a standard deviation of 10 pesos. Can this company be accused of paying inferior wages (less than the usual) at α=5%? Which of the following sets of hypotheses should be used in this study? A. Ho: μ = 150 vs. Ha: μ > 150 B. Ho: μ = 150 vs. Ha: μ < 150 C. Ho: μ = 148 vs. Ha: μ > 148 D. Ho: μ = 148 vs. Ha: μ < 148
Question 9 Two independent samples are selected from two populations with means µg and u2, respectively. Suppose a 99% confidence interval for u1 - H2 is (-1.65, 21.65), a 95% confidence interval is (0.2, 19.8), and a 90% confidence interval is (1.775, 18.225). In testing Ho : H1 - H2 = 0 versus H1: H1 - H2 0, the p-value is between 0.20 and 1.00 between 0.10 and 0.15 between 0.05 and 0.10 between 0.01 and 0.05. between 0.15 and 0.20

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