A sample of coarse aggregate was tested in a laboratory to find its moisture content. The wet weight of the sample found to be 5403.5 gr and its dry weight after drying the sample in the oven was 5235.1 gr.Find the moisture content of the aggregateIf the absorption of the aggregate was measured as 2.15%, calculate the percent of free water in the original sample.

Dry weight=5235.1gmWet weight=5403.5gmMoisture content=Wwet-WdryWdry×100Free water=MC-Absorption

Answered: A sample of coarse aggregate was tested…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

A sample of coarse aggregate was tested in a laboratory to find its moisture content. The wet weight of the sample found to be 5403.5 gr and its dry weight after drying the sample in the oven was 5235.1 gr.
Find the moisture content of the aggregate
If the absorption of the aggregate was measured as 2.15%, calculate the percent of free water in the original sample.

Expert Solution

Step 1

$D r y w e i g h t = 5235.1 g m W e t w e i g h t = 5403.5 g m M o i s t u r e c o n t e n t = \frac{W_{w e t} - W_{d r y}}{W_{d r y}} \times 100 F r e e w a t e r = M C - A b s o r p t i o n$