Answer ALL parts:(a)A sample of 5.034 g containing ammonium sulphate was warmedwith 50 cm³ of 0.400 M NaOH (excess). After the evolution ofammonia had ceased, the excess of NaOH was back titratedagainst HCI, requiring 33.0 cm³ of 0.1100 M acid. Calculate themass (in grams) of ammonium sulphate in the original sample.(NH4)2SO4 + 2NaOH → Na₂(SO4) + 2H₂O + 2NH3Note: RAM's: 0:15.999 H: 1.008 N:14.007(b)Calculate the pH of each of the following solutions and report youranswer to three decimal places:(a) 0.012 mol dm³ H₂SO4(b) 5.000 x 10 mol dm³ NaOHNOTE: Kw = 10 14S: 32.066D(c)A weak solution of ammonia (pKb: 4.767, 0.06 mol dm³, 20 cm³) istitrated against 0.03 mol dm³ HCI. Calculate:(i) pH at 0.00 cm³ HCI added(ii) pH at 12 cm³ HCI added(iii) pH at equivalence point

a.) To calculate the mass of ammonium sulfate , we first Calculate total moles of NaOH that are used…

A sample of 5.034 g containing ammonium sulphate was warmed with 50 cm³ of 0.400 M NaOH (excess). After the evolution of ammonia had ceased, the excess of NaOH was back titrated against HCI, requiring 33.0 cm³ of 0.1100 M acid. Calculate the mass (in grams) of ammonium sulphate in the original sample. (NH4)2SO4 + 2NaOH → Na₂(SO4) + 2H₂O + 2NH3 Note: RAM's: 0:15.999 H: 1.008 N:14.007 S: 32.066

A sample of 5.034 g containing ammonium sulphate was warmed with 50 cm³ of 0.400 M NaOH (excess). After the evolution of ammonia had ceased, the excess of NaOH was back titrated against HCI, requiring 33.0 cm³ of 0.1100 M acid. Calculate the mass (in grams) of ammonium sulphate in the original sample. (NH4)2SO4 + 2NaOH → Na₂(SO4) + 2H₂O + 2NH3 Note: RAM's: 0:15.999 H: 1.008 N:14.007 S: 32.066

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter14: Equilibria In Acid-base Solutions

Section: Chapter Questions

Problem 33QAP: A buffer is prepared in which the ratio [ H2PO4 ]/[ HPO42 ]is 3.0. (a) What is the pH of this...

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Hh.39.
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