A sample of 1600 computer chips revealed that 38 % of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed thatabove 35 % do not fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.02 level to support the company's claim?State the null and alternative hypotheses for the above scenario.AnswerHo:H₂:KeypadKeyboard ShortcutsTables

The question is about hypothesis testing.Given :Sample number of computer chips ( n ) = 1600Sample…

Answered: A sample of 1600 computer chips…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The recidivism rate for convicted sex offenders is 15%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 386 convicted sex offenders who were also drug addicts, 46 of them became repeat offenders. What can be concluded at the αα = 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 15% at αα = 0.10, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is different from 15%.…
There is a claim that playing e-sport increase food intake. The following table (Table 2) shows data on food intake (in Kcal) for 15 men on the 2 hours playing e-sport each night and for 15 men on the 4 hours playing e-sport each night. Conduct a hypothesis test with a = 0.05 to determine there is a significant difference in mean food intake for two different group. Table 2 2-hour playing e-sport 3586 4470 3068 5338 2221 4791 4435 3099 3187 3901 3868 3869 4878 3632 4518 4965 3918 1987 4993 5220 3653 3510 3338 4100 5792 4547 3319 3336 4304 4057 4-hour playing e-sport
In recent years, approximately 55% of eligible voters take the time to vote in presidential elections. A poll based on a random sample of 200 eligible voters finds that 128 plan to vote in the next presidential election. Does this data provide convincing evidence at the ?α = 0.05 level that the proportion of eligible voters who will take time to vote in the next presidential election differs from 0.55?
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 400 gram setting. Is there sufficient evidence at the 0.05 level that the bags are overfilled? Assume the population is normally distributed. State the null and alternative hypotheses for the above scenario. Answer Ho: Ha: Tables Keypad Keyboard Shortcuts
(a) Determine the null and alternative hypotheses that would be used to test the effectiveness of the marketing campaign. Ho: = μ 56 H₁: μ > 56 (Type integers or decimals. Do not round.) (b) A sample of 884 Americans provides enough evidence to conclude that marketing campaign was effective. Provide a statement that should be put out by the marketing department. O A. There is not sufficient evidence to conclude that the mean consumption of popcorn has risen. B. There is sufficient evidence to conclude that the mean consumption of popcorn has risen. C. There is sufficient evidence to conclude that the mean consumption of popcorn has stayed the same. D. There is not sufficient evidence to conclude that the mean consumption of popcorn has stayed the same.
In their advertisements, a new diet program would like to claim that their methods result in a mean weight loss of more than ten pounds in two weeks. In order to determine if this is a valid claim, they hire an independent testing agency that then selects twenty-five people to be placed on this diet. Which of the following is the correct hypotheses? a Ho: μ- 10 Ha: μ > 10 Ho: u > 10 Ha: u = 10 Ho: U = 10 Ha: u < 10 O d Ho: p = 10 Ha: u+ 10
please solve question 12
Can I have all 3 questions done, Thank you.
Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 23 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 10% level of significance. What is the level of significance? (b) State the null and alternate hypotheses. H0: p = 0.67; H1: p > 0.67 H0: p = 0.67; H1: p ≠ 0.67 H0: p < 0.67; H1: p = 0.67 H0: p = 0.67; H1: p < 0.67 What sampling distribution will you use? The Student's t, since np < 5 and nq < 5. The standard normal, since np < 5 and nq < 5. The standard normal, since np > 5 and nq > 5. The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) Find the P-value of the test statistic. (Round your answer to four decimal places.)…
Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?
please solve question 2 and 4
Question 12 Astudent was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 86. Which of the following is a correct interpretation of the interval 0.13 p < 0.27? Check all that are correct. With 90% confidence, the proportion of all students who take notes is between 0.13 and0.27. U There is a 90% chance that the proportion of the population is between 0.13 and 0.27. O There is a 90% chance that the proportion of notetakers in a sample of 86 students wilL be between 0.13 and 0.27. O The proprtion of all students who take notes is between 0.13 and 0.27, 90% of the time. OWith 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.13 and 0.27.

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