A sample of 10,000 cells are sampled from a patient. If the patient is pre-cancerous we can expect 0.1% of them to be abnormal, and otherwise we'd expect none of them to be abnormal. About 1% of patients sent for this test are actually pre-cancerous. A test is used to check cells for abnormality: the
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A sample of 10,000 cells are sampled from a patient. If the patient is
pre-cancerous we can expect 0.1% of them to be abnormal, and
otherwise we'd expect none of them to be abnormal. About 1% of
patients sent for this test are actually pre-cancerous. A test is used to
check cells for abnormality: the test is correct 99.5% of the time on
both normal and abnormal cells. Three (3) cells have this test applied
to them, and the test says one of them is abnormal and the rest are
normal. What is the probability that the patient is pre-cancerous?
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- A fitness course claims that it can improve an individual's physical ability. To test the effect of a physical fitness course on one's physical ability, the number of sit-ups that a person could do in one minute, both before and after the course, was recorded. Ten individuals are randomly selected to participate in the course. The results are displayed in the following table. Can it be concluded, from the data, that participation in the physical fitness course resulted in significant improvement? Let d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course)d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course). Use a significance level of α=0.05 for the test. Assume that the numbers of sit-ups are normally distributed for the population both before and after taking the fitness course. Sit-ups before 42 42 23 32 30 42 25 47 35 38 Sit-ups after…A behavioral scientist investigated whether there is a significant difference in the percentages of men and women who purchase silver-colored cars. The scientist selected a random sample of 50 men and a random sample of 52 women who had recently purchased a new car. Of the men selected, 16 had purchased a silver-colored car. Of the women selected, 9 had purchased a silver-colored car. Which of the following is the most appropriate method for analyzing the results? A two-sample zz-test for the difference in population proportions A A two-sample zz-test for the difference in sample proportions B A one-sample zz-test for a sample proportion C A one-sample zz-test for a population proportion D A one-sample zz-test for a difference in sample proportionsA fitness course claims that it can improve an individual's physical ability. To test the effect of a physical fitness course on one's physical ability, the number of sit-ups that a person could do in one minute, both before and after the course, was recorded. Ten individuals are randomly selected to participate in the course. The results are displayed in the following table. Can it be concluded, from the data, that participation in the physical fitness course resulted in significant improvement? Let d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course)d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course). Use a significance level of α=0.05 for the test. Assume that the numbers of sit-ups are normally distributed for the population both before and after taking the fitness course. Sit-ups before 42 42 23 32 30 42 25 47 35 38 Sit-ups after…
- Fewer young people are driving. In 1995, 63.9% of people under 20 years old who were eligible had a driver's license. Bloomberg reported that percentage had dropped to 41.7% in 2016. Suppose these results are based on a random sample of 1,200 people under 20 years old who were eligible to have a driver's license in 1995 and again in 2016.Is the flu making us sicker? A question of interest at the latest health summit was whether the latest strain of flu was causing adults to run a higher fever than previous strains. The average temperature for previous strains of flu was 101.4 degrees. A random sample of eighteen adults with the latest strain of flu was obtained. The data below represents their highest temperature while sick with the latest flu strain. Based on the data, can we conclude that the latest strain of flu is causing patients to run a higher fever, on average, than previous strains of flu? Let the probability of making a Type-I error be 10%. 102.1 101.8 100.9 103.8 102.8 100.8 102.5 102.0 103.1 104.0 104.2 101.1 100.3 101.9 101.7 101.8 102.3 104.1Green Tea and Prostate Cancer A preliminary study suggests a benefit from green tea for those at risk of prostate cancer. The study involved 60 men with PIN lesions, some of which turn into prostate cancer. Half the men, randomly determined, were given 600 mg a day of a green tea extract while the other half were given a placebo. The study was double-blind, and the results after one year are shown in the table below. Treatment Cancer No Cancer Green Tea 1 29 Placebo 9 21 (a) Test at a 5% significant level to see if the sample provide evidence that taking green tea extract reduces the risk of developing prostate cancer. (b) Find 98% confidence interval for the difference between two population proportions of men with PIN lesions who get prostate cancer after taking green tea extract and after taking placebo for a year. Interpret the C.I. result.
- Hospital floors: Hospital floors are usually bare tiles instead of carpet. Carpets will decrease noise but might increase germ growth. To study this, researchers installed carpet in 8 of 16 hospital rooms. They randomly selected the rooms to carpet. The other rooms had bare tiles. After two weeks of normal use, they collected air samples from the rooms and counted the bacteria in each sample. Based on this description of the experiment, which of the following is a part of the experiment design? Check all that apply. Group of answer choicesHow long it takes paint to dry can have an impact on the production capacity of a business. An auto body & paint business invested in a paint-drying robot to speed up its process. An interesting question is, "Do all paint-drying robots have the same drying time?" To test this, suppose we sample five drying times for each of different brands of paint-drying robots. The time in minutes until the paint was dry enough for a second coat to be applied was recorded. Suppose the following data were obtained. Robot 4 Robot 1 128 138 134 125 135 Robot 2 143 134 142 147 | Ho: M₁ = 1₂ = 13 = 14 H₂: M₁ # M₂ # Hz # H4 124 4ܐ = 3ܬܐ = 2ܬܐ = 1ܐ :Ha Robot 3 132 142 | Ho: M₁ # M₂ # M3 # H4 H₂: M₁ = 1₂ = 13 = 14 138 135 128 ⒸH₁: M₁ = H₂ = 143 = 14 H: Not all the population means are equal. 151 142 At the α = 0.05 level of significance, test to see whether the mean drying time is the same for each type of robot. State the null and alternative hypotheses. O Ho: Not all the population means are equal. 136…You are concerned that nausea may be a side effect of Tamiflu, but you cannot just give Tamiflu to patients with the flu and say that nausea is a side effect if people become nauseous. This is because nausea is common for people who have the flu.Past studies state that about 33% of people who get the flu experience nausea. You collected data on 2248 patients who were taking Tamiflu to relieve symtoms of the flu, and found that 810 experienced nausea. You decide to carry out a simulation to test the claim that the percentage of people who take Tamiflu for the relief of flu symtoms and experience nausea is greater than 33%.a) Identify the null and alternative hypotheses.H0H0: ? p = p ≠ p < p > p ≤ p ≥ μ = μ ≠ μ < μ > μ ≤ μ ≥ H1H1: ? p = p ≠ p < p > p ≤ p ≥ μ = μ ≠ μ < μ > μ ≤ μ ≥
- A fitness course claims that it can improve an individual's physical ability. To test the effect of a physical fitness course on one's physical ability, the number of sit-ups that a person could do in one minute, both before and after the course, was recorded. Ten individuals are randomly selected to participate in the course. The results are displayed in the following table. Can it be concluded, from the data, that participation in the physical fitness course resulted in significant improvement? Let d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course)d=(number of sit-ups that can be done after taking the course)−(number of sit-ups that can be done prior to taking the course). Use a significance level of α=0.05α=0.05 for the test. Assume that the numbers of sit-ups are normally distributed for the population both before and after taking the fitness course. Sit-ups before 3030 3939 5353 3838 3333 5151 2222 3838…In the article “Explaining an Unusual Allergy,” appearing on the Everyday Health Network, Dr. A. Feldweg explained that allergy to sulfites is usually seen in patients with asthma. The typical reaction is a sudden increase in asthma symptoms after eating a food containing sulfites. Studies are performed to estimate the percentage of the nation’s 10 million asthmatics who are allergic to sulfites. In one survey, 38 of 500 randomly selected U.S. asthmatics were found to be allergic to sulfites. Find and interpret a 95% confidence interval for the proportion p of all U.S. asthmatics who are allergic to sulfites.What is the value of the sample test statistic? (Test the difference p₁ - P2. Do not use rounded values. Round your final answer to two decimal places.) (c) Find (or estimate) the P-value. (Round your answer to four decimal places.) Sketch the sampling distribution and show the area corresponding to the P-value. 0-3 -2 -2 -1 -1 0 Read It 0 1 1 Watch it 2 2 3 0-3 ^ -1 0 1 -2 -2 -1 0 1 O At the a = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant. O At the a = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant. 2 2 (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level a? O At the a = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. O At the a= 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. 3…
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