A salesman makes initial telephone contact with potential customers in an effort to assess whether a follow-up visit to their homes is likely to be worthwhile. His experience suggests that 40% of the initial contacts lead to follow-up visits. Suppose he contacts 100 people by telephone and the sample proportion of the follow-up visit is calculated. Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one correct answers. Di. The sample proportion has a normal distribution with a mean of 0.40 and a standard deviation of 04.04 100 Dil. The sample proportion has a normal distribution with a mean of 0.40 and a standard deviation of 0.6, Oiii. The probability that the sample proportion of the follow-up visit is more than 50% is P(p>0.5)=P(z>04-05)=P(z>-2.04) = 1-0.0207 = 0.9793. iv. The probability that the sample proportion of the follow-up visit is more than 50% is P(p>0.5)=P(2: = P(Z > 2.04)=1-0.9793= 0.0207. 0.5-0.4 0.049 -0.049

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A salesman makes initial telephone contact with potential customers in an effort to assess whether a follow-up
visit to their homes is likely to be worthwhile. His experience suggests that 40% of the initial contacts lead to
follow-up visits. Suppose he contacts 100 people by telephone and the sample proportion of the follow-up visit is
calculated.
Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one
correct answers.
i. The sample proportion has a normal distribution with a mean of 0.40 and a standard deviation of 04x0.4
= 0.049.
100
Oil. The sample proportion has a normal distribution with a mean of 0.40 and a standard deviation of 0.6.
iii. The probability that the sample proportion of the follow-up visit is more than 50% is
P(p>0.5) = P(z>04-05)=P(z>-2.04) = 1-0.0207 = 0.9793.
iv. The probability that the sample proportion of the follow-up visit is more than 50% is
P(p>0.5)=P(2> 05 = P(Z > 2.04) = 1-0.9793= 0.0207.
0.5-0.41
0.049
Transcribed Image Text:A salesman makes initial telephone contact with potential customers in an effort to assess whether a follow-up visit to their homes is likely to be worthwhile. His experience suggests that 40% of the initial contacts lead to follow-up visits. Suppose he contacts 100 people by telephone and the sample proportion of the follow-up visit is calculated. Which of the following statements is (are) correct? This is a multiple-answer question. It may have more than one correct answers. i. The sample proportion has a normal distribution with a mean of 0.40 and a standard deviation of 04x0.4 = 0.049. 100 Oil. The sample proportion has a normal distribution with a mean of 0.40 and a standard deviation of 0.6. iii. The probability that the sample proportion of the follow-up visit is more than 50% is P(p>0.5) = P(z>04-05)=P(z>-2.04) = 1-0.0207 = 0.9793. iv. The probability that the sample proportion of the follow-up visit is more than 50% is P(p>0.5)=P(2> 05 = P(Z > 2.04) = 1-0.9793= 0.0207. 0.5-0.41 0.049
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