**Problem Statement:**A round disk of 200-mm diameter is blanked from a strip of 3.0-mm, half-hard cold-rolled steel whose shear strength is 300 MPa, and clearance allowance = 0.075. Determine:a. the appropriate punch and die diameters, and b. blanking force **Equation to Use:****Clearance Allowance Value for Three Sheet Metal Groups. Compiled from [3].**| Metal Group | \( A_c \) ||------------------------------------------------------------------------------------------------|-----------|| 1100S and 5052S aluminum alloys, all tempers. | 0.045 || 2024ST and 6061ST aluminum alloys; brass, all tempers; soft cold-rolled steel, soft stainless steel. | 0.060 || Cold-rolled steel, half hard; stainless steel, half-hard and full-hard. | 0.075 | The table provides clearance allowance values for different metal groups to guide the determination of punch and die diameters, as well as the necessary blanking force for various materials based on their shear properties.

Given data: d=200 mmt=3 mmτ=300 MPaAc=0.075 Need to determine the punch, die diameters and blanking…

Answered: A round disk of 200-mm diameter is…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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