A rod is used to hang a load (force) of 1000 N. There are 4 ingredients with their respective strengths. Create a program to create a bar diameter table, if using the 4 materials. Example: Copper Steel Material. Aluminum. Bronze Strength(N/mm2) 2000. 1600. 1400. 1700 Rod Diameter: Ingredient. Copper Steel. Aluminum. Bronze Diameter. (mm) …. …. …. ….. Note: Strength is the maximum stress the material can withstand Stress S = force/sectional area S=force/A A = force/Smax Cross-sectional area A = 3.14 x d2 /4 d = root(4xA/3.14) Instructions: Make a list to
A rod is used to hang a load (force) of 1000 N. There are 4 ingredients with their respective strengths. Create a program to create a bar diameter table, if using the 4 materials. Example: Copper Steel Material. Aluminum. Bronze Strength(N/mm2) 2000. 1600. 1400. 1700 Rod Diameter: Ingredient. Copper Steel. Aluminum. Bronze Diameter. (mm) …. …. …. ….. Note: Strength is the maximum stress the material can withstand Stress S = force/sectional area S=force/A A = force/Smax Cross-sectional area A = 3.14 x d2 /4 d = root(4xA/3.14) Instructions: Make a list to
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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A rod is used to hang a load (force) of 1000 N.
There are 4 ingredients with their respective strengths.
Create a program to create a bar diameter table, if using the 4 materials.
Example: Copper Steel Material. Aluminum. Bronze
Strength(N/mm2) 2000. 1600. 1400. 1700
Rod Diameter:
Ingredient. Copper Steel. Aluminum. Bronze
Diameter. (mm) …. …. …. …..
Note: Strength is the maximum stress the material can withstand
Stress S = force/sectional area S=force/A A = force/Smax
Cross-sectional area A = 3.14 x d2 /4 d = root(4xA/3.14)
Instructions: Make a list to store the ingredient names and strengths
Create in a python program
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