A rod holds a uniform positive charge density. Draw the approximate electric field vectors at the points P, and P2, paying careful attention to the directions.
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- Points A, B, and C are at the vertices of an equilateral triangle. A certain positive charge q placed at A produces an electric field of magnitude 311 N/C at C. Suppose a second, identical charge is placed at B. What is the magnitude of the new electric field at C?A -1.11 nC point charge is located inside a cavity of a hollow sphere of conducting material with charge 6.72 nC and of radius 10.0 cm. Calculate the electric field 0.473 m from the point charge in units of N/C. Assume answers are in the radial direciton such that if the field points radially away your answer will be positive and if the field points radially in your answer will be negative. Give your numerical result to 3 significant figures and type in the units after your numerical answer.Written or image answers please, thank you!
- Please AsapWhat is the magnitude of the x-component of the electric field at the origin. Let L = 3.3 mA cube has positive charge +Q in all corners except for one, which has a negative point charge - Q. Let the distance from any corner to the center of the cube be r. What is the magnitude and direction of the of electric field at the center of the cube (point P)?
- Could you please explain, why the electric field will be along - direction?È= [dE = [k9 .. Start with... f... dxA negative line of charge is on the negative y axis with its top end at the origin as shown in the figure below. The charge is uniformly distributed along the line. Point P is on the positive y axiS as shown in the figure. y The the length of the line of charge is 3.17 m, the total charge on the line is -787.9 nC and point P is 3.15 m from the origin. Find the magnitude of the electric field at point P due to the line of charge. (in N/C) OA: 3.15×10²| OB: 3.56×102| 0C: 4.02×102| OD: 4.54×102| OE: 5.13×102|| OF: 5.80×102|| OG: 6.56×102|| OH: 7.41×102 Submit Answer Tries 0/99