Shown in the figure below is an arc of charge. The arc carries a charge density, ? that is distributed uniformly around the arc from ? = -?0 to ? = +?0. The arc has a radius R and you are to calculate the magnitude of the field at the origin.
Shown in the figure below is an arc of charge. The arc carries a charge density, ? that is distributed uniformly around the arc from ? = -?0 to ? = +?0. The arc has a radius R and you are to calculate the magnitude of the field at the origin.
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Shown in the figure below is an arc of charge. The arc carries a charge density, ? that is distributed uniformly around the arc from ? = -?0 to ? = +?0. The arc has a radius R and you are to calculate the magnitude of the field at the origin.
![Which is the natural coordinate system to use for this integral?
Spherical
Cartesian
Cylindrical
R
00
#
00
R
How many dimensions should you integrate over?
1
O 2
Determine the length element, dL = Rda
Determine the charge element, dQ = λRda
Determine the distance, s = R
Determine the so-called, cos(a) =
Determine the integrand, f
cos(a) da
4лkR
4nksin (a)
Determine the lower bound of the integral:
Determine the upper bound of the integral:
Determine the final result of the integration:
X
47kRsin (-00)
2
4nkR
X
sin/ (%)
2
4TkR
X
-00
100
sin (a)
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Transcribed Image Text:Which is the natural coordinate system to use for this integral?
Spherical
Cartesian
Cylindrical
R
00
#
00
R
How many dimensions should you integrate over?
1
O 2
Determine the length element, dL = Rda
Determine the charge element, dQ = λRda
Determine the distance, s = R
Determine the so-called, cos(a) =
Determine the integrand, f
cos(a) da
4лkR
4nksin (a)
Determine the lower bound of the integral:
Determine the upper bound of the integral:
Determine the final result of the integration:
X
47kRsin (-00)
2
4nkR
X
sin/ (%)
2
4TkR
X
-00
100
sin (a)
Your answer cannot be understood or graded. More Information
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