A reversible reaction is carried out in a constant volume batch reactor as shown below. Derive an expression that relates the amount of A with its initial amount, at any time t. The forward rate constant is k,, the backward rate constant is k2. The values of a and b are stoichiometric coefficients of the reactant and product A and R, respectively. 1.5A +R -rA = kı[A]ª – k2[R]®
A reversible reaction is carried out in a constant volume batch reactor as shown below. Derive an expression that relates the amount of A with its initial amount, at any time t. The forward rate constant is k,, the backward rate constant is k2. The values of a and b are stoichiometric coefficients of the reactant and product A and R, respectively. 1.5A +R -rA = kı[A]ª – k2[R]®
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![A reversible reaction is carried out in a constant volume batch reactor as shown below. Derive an expression
that relates the amount of A with its initial amount, at any time t. The forward rate constant is k,, the
backward rate constant is k2. The values of a and b are stoichiometric coefficients of the reactant and
product A and R, respectively.
1.5A +R
-TA = ka[A]ª – kz[R]®
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7af8a420-e8e7-454c-8cb2-169d52db915a%2F22e72ac2-e110-470a-8b72-4513523328b0%2Flj3tx97_processed.png&w=3840&q=75)
Transcribed Image Text:A reversible reaction is carried out in a constant volume batch reactor as shown below. Derive an expression
that relates the amount of A with its initial amount, at any time t. The forward rate constant is k,, the
backward rate constant is k2. The values of a and b are stoichiometric coefficients of the reactant and
product A and R, respectively.
1.5A +R
-TA = ka[A]ª – kz[R]®
%3D
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